When tertiary butyl alcohol is passed over reduced copper, the reaction taking placed is

Options

A. Secondary butyl alcohol is formed
B. 2-Methylpropene is formed
C. 1-Butene is formed .
D. Butanal is formed .

Answer

To solve the question about the reaction that occurs when tertiary butyl alcohol is passed over reduced copper, we can follow these steps:

### Step 1: Identify the Reactant
The reactant in this case is tertiary butyl alcohol, which has the chemical structure \( (CH_3)_3COH \).

### Step 2: Understand the Reaction Conditions
The question states that the tertiary butyl alcohol is passed over reduced copper. Reduced copper acts as a catalyst in this reaction and typically facilitates dehydration reactions.

### Step 3: Analyze the Reaction Mechanism
When tertiary butyl alcohol is heated in the presence of reduced copper, a dehydration reaction occurs. This means that a water molecule (\( H_2O \)) is eliminated from the alcohol.

### Step 4: Identify the Products
During the dehydration of tertiary butyl alcohol, one hydroxyl group (OH) and one hydrogen atom from the alcohol are removed, resulting in the formation of an alkene. The product formed from the dehydration of tertiary butyl alcohol is isobutylene (2-methylpropene), which has the structure \( CH_2=C(CH_3)_2 \).

### Step 5: Write the Balanced Reaction
The overall reaction can be summarized as follows:
\[ (CH_3)_3COH \xrightarrow{\text{Cu, heat}} CH_2=C(CH_3)_2 + H_2O \]

### Conclusion
When tertiary butyl alcohol is passed over reduced copper and heated, it undergoes dehydration to form isobutylene and water.

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