When phenol in treated with excess bromine water, it gives

Options

A. 2 ,4, 6 - tribromophenol
B. o-bromophenol
C. p-bromophenol
D. bromobenzene.

Explanation

To solve the question of what product is formed when phenol is treated with excess bromine water, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant in this case is phenol (C6H5OH).

2. **Understand the Reaction Conditions**:
- The reaction involves treating phenol with excess bromine water (Br2 in water).

3. **Recognize the Directing Effects**:
- The hydroxyl group (-OH) in phenol is an activating group and is ortho-para directing. This means that bromine will preferentially substitute at the ortho and para positions relative to the -OH group.

4. **Draw the Structure of Phenol**:
- The structure of phenol is a benzene ring with a hydroxyl group attached.

5. **Substitution Reaction**:
- When phenol is treated with excess bromine, bromine atoms will substitute the hydrogen atoms at the ortho and para positions. Since we have excess bromine, all available positions will be substituted.

6. **Identify the Product**:
- The product formed will have three bromine atoms substituted at the 2, 4, and 6 positions of the benzene ring, resulting in 2,4,6-tribromophenol.

7. **Final Answer**:
- Therefore, when phenol is treated with excess bromine water, it gives **2,4,6-tribromophenol**.

### Conclusion:
The correct answer is **(A) 2,4,6-tribromophenol**.

---