The number of oxygen atoms present in 1 mole of oxalic acids dihydrate is

Options

A. `6xx10^23`
B. `6.022xx10^34`
C. `7.22xx10^23`
D. `36.13xx10^23`

Explanation

To find the number of oxygen atoms present in 1 mole of oxalic acid dihydrate, we can follow these steps:

### Step 1: Determine the formula of oxalic acid dihydrate
Oxalic acid has the chemical formula \( C_2H_2O_4 \). Since it is a dihydrate, we need to add 2 water molecules, which have the formula \( H_2O \). Therefore, the formula for oxalic acid dihydrate is:
\[ C_2H_2O_4 \cdot 2H_2O \]

### Step 2: Count the number of oxygen atoms in the formula
In the formula \( C_2H_2O_4 \cdot 2H_2O \):
- The oxalic acid part \( C_2H_2O_4 \) contains 4 oxygen atoms.
- Each water molecule \( H_2O \) contains 1 oxygen atom, and since there are 2 water molecules, this contributes an additional 2 oxygen atoms.

Thus, the total number of oxygen atoms in one molecule of oxalic acid dihydrate is:
\[ 4 \text{ (from oxalic acid)} + 2 \text{ (from water)} = 6 \text{ oxygen atoms} \]

### Step 3: Calculate the number of oxygen atoms in 1 mole of oxalic acid dihydrate
1 mole of any substance contains Avogadro's number of molecules, which is approximately \( 6.022 \times 10^{23} \) molecules. Therefore, in 1 mole of oxalic acid dihydrate, the total number of oxygen atoms is:
\[ 6 \text{ (oxygen atoms per molecule)} \times 6.022 \times 10^{23} \text{ (molecules)} = 3.6132 \times 10^{24} \text{ oxygen atoms} \]

### Final Answer
The number of oxygen atoms present in 1 mole of oxalic acid dihydrate is approximately:
\[ 3.6132 \times 10^{24} \text{ oxygen atoms} \]

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