Home
Class 11
CHEMISTRY
Calculate the number of aluminium ions p...

Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.
(Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27 u)

A

`6.023xx10^20` ions

B

3 ions

C

`6.023xx10^23` ions

D

9 ions

Text Solution

AI Generated Solution

To calculate the number of aluminum ions present in 0.051 g of aluminum oxide (Al₂O₃), we will follow these steps: ### Step 1: Calculate the molar mass of aluminum oxide (Al₂O₃) The molar mass of aluminum oxide can be calculated using the atomic masses of aluminum (Al) and oxygen (O). - Atomic mass of Al = 27 g/mol - Atomic mass of O = 16 g/mol ...
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NCERT FINGERTIPS ENGLISH|Exercise HOTS|9 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    NCERT FINGERTIPS ENGLISH|Exercise EXEMPLAR PROBLEMS|10 Videos
  • REDOX REACTIONS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos
  • STATES OF MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

Calculate the number of atoms present in one drop of water having mass 1.8 g .

Atomic number of an ion is the same as the number of electrons present in it.

Isotopes have same number of atomic mass

Calculate the mass in gm of 2g atom of Mg-

Calculate the mass of 2.5 g atom of oxygen.

Calculate the mass of aluminium oxide formed when 27 g of aluminium foil is burnt completely in oxygen. (Al= 27, O = 16)

The number of atoms present in 1 g of hydrogen is the same as that in 1 g of oxygen.

The number of lone pair present in N-atom in NH_(4)^(+) ion is

Calculate the number of gram atoms present in the following masses. (i) 12.69 g of hydrogen, (ii) 40.089 g of calcium (Given, atomic mass of H = 1.008 amu and atomic mass of Ca = 40.08 amu)

A quantity of aluminium has a mass of 54.0 g . What is the mass of the same number of magnesium atoms ?.