How many oxygen atoms will be present in 88 g of `CO_2` ?

Options

A. `24.08xx10^23`
B. `6.023xx10^23`
C. `44xx10^23`
D. `22xx10^24`

Explanation

To determine how many oxygen atoms are present in 88 g of \( CO_2 \), we can follow these steps:

### Step 1: Calculate the molar mass of \( CO_2 \)
The molar mass of carbon dioxide (\( CO_2 \)) can be calculated as follows:
- The molar mass of carbon (C) = 12 g/mol
- The molar mass of oxygen (O) = 16 g/mol

Since there are 2 oxygen atoms in \( CO_2 \), the molar mass of \( CO_2 \) is:
\[ \text{Molar mass of } CO_2 = 12 \, \text{g/mol} + (2 \times 16 \, \text{g/mol}) = 12 + 32 = 44 \, \text{g/mol} \]

### Step 2: Calculate the number of moles of \( CO_2 \)
Using the formula:
\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]
We can calculate the number of moles of \( CO_2 \):
\[ \text{Number of moles of } CO_2 = \frac{88 \, \text{g}}{44 \, \text{g/mol}} = 2 \, \text{moles} \]

### Step 3: Calculate the number of molecules of \( CO_2 \)
Using Avogadro's number (\( N_A = 6.02 \times 10^{23} \, \text{molecules/mol} \)), the number of molecules in 2 moles of \( CO_2 \) is:
\[ \text{Number of molecules of } CO_2 = 2 \, \text{moles} \times N_A = 2 \times 6.02 \times 10^{23} \, \text{molecules} \]

### Step 4: Calculate the number of oxygen atoms
Each molecule of \( CO_2 \) contains 2 oxygen atoms. Therefore, the total number of oxygen atoms is:
\[ \text{Number of oxygen atoms} = \text{Number of molecules of } CO_2 \times 2 \]
Substituting the value from Step 3:
\[ \text{Number of oxygen atoms} = (2 \times 6.02 \times 10^{23}) \times 2 = 4 \times 6.02 \times 10^{23} \]

### Step 5: Calculate the final answer
Now, we perform the multiplication:
\[ \text{Number of oxygen atoms} = 4 \times 6.02 \times 10^{23} = 24.08 \times 10^{23} \]

### Final Answer
Thus, the number of oxygen atoms present in 88 g of \( CO_2 \) is:
\[ 24.08 \times 10^{23} \]