In a reaction container, 100g of hydrogen and 100 g of `Cl_2` are mixed for the formation of HCl gas. What is the limiting reagent and how much HCl is formed in the reaction ?

Options

A. `H_2` is limiting reagent and 36.5 g of HCl are formed.
B. `Cl_2` is limiting reagent and 102.8 g of HCl are formed.
C. `H_2` is limiting reagent and 142 g of HCl are formed.
D. `Cl_2` is limiting reagent and 73 g of HCl are formed.

Explanation

To solve the problem of determining the limiting reagent and the amount of HCl formed in the reaction between hydrogen (H₂) and chlorine (Cl₂), we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between hydrogen and chlorine can be represented by the following balanced equation:
\[ \text{H}_2 + \text{Cl}_2 \rightarrow 2 \text{HCl} \]

### Step 2: Calculate the number of moles of each reactant
To find the limiting reagent, we need to calculate the number of moles of hydrogen and chlorine.
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