If 40g of `CaCO_3` is treated with 40g of HCl, which of the reactants will acts as limiting reagent?

Options

A. `CaCO_3`
B. HCl
C. Both (a) and (b)
D. None of these

Explanation

To determine which reactant acts as the limiting reagent when 40g of CaCO₃ is treated with 40g of HCl, we can follow these steps:

### Step 1: Write the balanced chemical equation.
The reaction between calcium carbonate (CaCO₃) and hydrochloric acid (HCl) can be represented as:
\[ \text{CaCO}_3 + 2 \text{HCl} \rightarrow \text{CaCl}_2 + \text{H}_2\text{O} + \text{CO}_2 \]

### Step 2: Identify the molar masses of the reactants.
- Molar mass of CaCO₃ = 40 (Ca) + 12 (C) + 3 × 16 (O) = 100 g/mol
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