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Chlorine gas is prepared by reaction of ...

Chlorine gas is prepared by reaction of `H_2SO_4` with `MnO_2` and NaCl. What volume of `Cl_2` will be produced at STP if 50 g of NaCl is taken in the reaction ?

A

1.915 L

B

22.4 L

C

11.2 L

D

9.57 L

Text Solution

AI Generated Solution

To solve the problem of how much chlorine gas (Cl₂) will be produced from the reaction of sulfuric acid (H₂SO₄) with manganese dioxide (MnO₂) and sodium chloride (NaCl), we will follow these steps: ### Step 1: Write the balanced chemical equation The reaction can be represented as: \[ 2 \text{NaCl} + 3 \text{H}_2\text{SO}_4 + \text{MnO}_2 \rightarrow 2 \text{NaHSO}_4 + \text{MnSO}_4 + \text{Cl}_2 + 2 \text{H}_2\text{O} \] ### Step 2: Calculate the number of moles of NaCl To find the number of moles, we use the formula: ...
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