Home
Class 11
CHEMISTRY
A compound on analysis was found to cont...

A compound on analysis was found to contain the following composition :
`Na=14.31%,S=9.97%,O=69.50 %and H=6.22 %`
Calculate the molecular formula of the compound assuming that the whole of hydrogen in the compound is present as water of crystallisation. Molecular mass of the compound is 322.

A

`Na_2SO_4`

B

`Na_2SO_(4) . 10H_2O`

C

`Na_2SH_10O_12`

D

`Na_2SO_(4) . 7H_2O`

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Calculate the moles of each element We start by calculating the number of moles of each element in the compound using the given percentages and the molar masses of the elements. - **Molar Masses**: - Sodium (Na): 23 g/mol - Sulfur (S): 32 g/mol ...
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NCERT FINGERTIPS ENGLISH|Exercise EXEMPLAR PROBLEMS|10 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NCERT FINGERTIPS ENGLISH|Exercise ASSERTION AND REASON|15 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NCERT FINGERTIPS ENGLISH|Exercise NCERT Exemplar|11 Videos

  • REDOX REACTIONS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

  • STATES OF MATTER

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

A compound on analysis gave the following percentage composition : Na= 14.31%, S = 9.97%, H = 6.22%, O = 69.50%. Calculate the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322. (At. wt. of Na = 23, S = 32, H = 1, O = 16)

An inorganic compound on analysis was found to have following composition : Mg = 9.76%, S = 13.01%, O = 26.01%, H_2O = 51.22% Calculate the empirical formula of the compound.

A chemical compound is found to have the following composition : C = 19.5%, Fe = 15.2%, N = 22.8%, K = 42.5% Calculate the empirical formula of the compound. What will be the molecular formula if the molecular mass of the compound is 368 ?

A crystalline compound when heated became anhydrous by losing 51.2 % of the mass. On analysis, the anhydrous compound gave the following percentage composition: Mg = 20.0 %, S = 26.66 % and O = 53.33 %, Calculate the molecular formula of the anhydrous compound and crystalline compound. The molecular mass of anhydrous compound is 120 u.

A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55 Its VD is 44. Find the molecular formula of the compound.

An organic compound has 68.327% C, 6.406% H, 25.267% CI. Calculate the molecular formula of the compound if its vapour density is 70.25.

A compound contains 42.3913 % K,15.2173 % Fe,19.5652 % C and 22.8260 % N . The molecular mass of the compound is 368 u. Find the molecular formula of the compound.

A compound on analysis gave the follwing result C=54.54%, H=9.09% and vapour density of compound = 88.Determine the molecular formula of the compound.

A compound contains C=40%,O=53.5% , and H=6.5% the empirical formula formula of the compound is:

A hydrocarbon contain 80% C . The vapour density of compound in 30 . Molecular formula of compound is :-