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If the concentration of glucose (C(6)H(1...

If the concentration of glucose `(C_(6)H_(12)O_(6))` in blood is 0.9 g `L^(-1)`, what will be the molarity of glucose in blood?

A

5 M

B

50 M

C

0.005 M

D

0.5 M

Text Solution

Verified by Experts

The correct Answer is:
C
Molarity `=("W_B (in g)")/(M_(B)("in g mol"^(-1))xx "Volume of solution (in L)")`
`=(Conc. ("in g L"^(-1)))/(M_(B) ("in g mol"^(-1)))= (0.9)/(180) = 0.005M (therefore " molar mass of " C_6H_12O_6= 180 g mol^(-1))`
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