One mole of any substance contains `6.022xx10^(23)` atoms/molecules. Number of molecules of `H_(2)SO_(4)` present in 100mL of 0.02M `H_2SO_(4)` solution is

Options

A. `12.044xx10^20`
B. `6.022xx10^23`
C. `1xx10^23`
D. `12.044xx10^23`

Explanation

To find the number of molecules of \( H_2SO_4 \) present in 100 mL of a 0.02 M \( H_2SO_4 \) solution, we can follow these steps:

### Step 1: Understand the relationship between molarity, moles, and volume
Molarity (M) is defined as the number of moles of solute per liter of solution. The formula to calculate moles from molarity and volume is:

\[ \text{Moles} = \text{Molarity} \times \text{Volume in liters} \]
...