How many number of electrons are present in a particle which carries a charge of `5.5xx10^(-16)C?`

Options

A. 3432
B. 1560
C. 8240
D. 2432

Explanation

To determine how many electrons are present in a particle that carries a charge of \(5.5 \times 10^{-16} \, \text{C}\), we can follow these steps:

### Step 1: Understand the relationship between charge and electrons
The total charge \(Q\) of a particle can be expressed in terms of the number of electrons \(n\) and the charge of a single electron \(e\). The formula is:
\[ Q = n \times e \]
Where:
- \(Q\) is the total charge,
- \(n\) is the number of electrons,
- \(e\) is the charge of one electron.

### Step 2: Rearrange the formula to solve for \(n\)
To find the number of electrons \(n\), we can rearrange the formula:
\[ n = \frac{Q}{e} \]

### Step 3: Substitute the known values
We know:
- \(Q = 5.5 \times 10^{-16} \, \text{C}\)
- The charge of one electron \(e = 1.6022 \times 10^{-19} \, \text{C}\)

Now, substituting these values into the formula:
\[ n = \frac{5.5 \times 10^{-16}}{1.6022 \times 10^{-19}} \]

### Step 4: Perform the calculation
Now, we will calculate \(n\):
\[ n = \frac{5.5}{1.6022} \times \frac{10^{-16}}{10^{-19}} = \frac{5.5}{1.6022} \times 10^{3} \]
Calculating the first part:
\[ \frac{5.5}{1.6022} \approx 3.432 \]
Now, multiplying by \(10^{3}\):
\[ n \approx 3.432 \times 10^{3} \approx 3432 \]

### Conclusion
Thus, the number of electrons present in the particle is approximately **3432**.