An element has atomic number 79.Predict the group and period in which the element is placed.

Options

A. `2^(nd)` group,`7^(th)` period
B. `11^(th)` group,`6^(th)period`
C. `13^(th)` group,`6^(th)`period
D. `12^(th)`group, `6^(th)` period

Answer

B

Explanation

`Z=79[Xe]4f^(14)5d^(10)6s^(1)=(n=6)` As m=6,the element belongs to `6^(th) period. Group=ns+(n-1)d,1+10=11`