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The first (IE(1)) and second (IE(2)) ion...

The first `(IE_(1))` and second `(IE_(2))` ionisation energies `(k J mol^(-1))` of a new elements designated by roman numerals are shown below:
`{:(,,IE_(1),IE_(2),),(I,,2370,5250,),(II,,520,7300,),(III,,900,1800,),(IV,,1700,3400,):}`
Which of the above elements is likely to be :
a. A reactive metal
b. A reactive non-metal
c. a noble gas
d. A metal that forms a stable binary halide of the formula `AX_(2)` (`X=` the halogen).

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To solve the problem, we need to analyze the given ionization energies (IE) for the four elements and determine which element corresponds to each of the categories: reactive metal, reactive non-metal, noble gas, and a metal that forms a stable binary halide of the formula AX₂. ### Step-by-Step Solution: 1. **Understanding Ionization Energies:** - Ionization energy is the energy required to remove an electron from an atom. The first ionization energy (IE₁) is the energy needed to remove the first electron, and the second ionization energy (IE₂) is for removing the second electron. - A large jump in ionization energy between IE₁ and IE₂ indicates that after the removal of the first electron, the atom achieves a stable electron configuration (like that of a noble gas). 2. **Analyzing Each Element:** - **Element I:** IE₁ = 2370 kJ/mol, IE₂ = 5250 kJ/mol - There is a significant increase from IE₁ to IE₂, indicating that after losing the first electron, the atom reaches a stable configuration. This suggests it is a reactive metal (likely from Group 1). - **Element II:** IE₁ = 520 kJ/mol, IE₂ = 7300 kJ/mol - There is a very large jump in ionization energy, suggesting that this element is a non-metal, likely a halogen, as it requires a lot of energy to remove the second electron after achieving a stable configuration. - **Element III:** IE₁ = 900 kJ/mol, IE₂ = 1800 kJ/mol - The increase from IE₁ to IE₂ is moderate, indicating that this element is likely a metal that can lose two electrons but does not have a drastic jump, suggesting it may form stable compounds. - **Element IV:** IE₁ = 1700 kJ/mol, IE₂ = 3400 kJ/mol - Similar to Element III, the increase is moderate, but both values are relatively high, indicating this could also be a noble gas. 3. **Matching Elements to Categories:** - **a. Reactive Metal:** Element I (2370, 5250) - **b. Reactive Non-Metal:** Element II (520, 7300) - **c. Noble Gas:** Element IV (1700, 3400) - **d. Metal that forms stable binary halide AX₂:** Element III (900, 1800) ### Final Answers: - a. Element I is a reactive metal. - b. Element II is a reactive non-metal. - c. Element IV is a noble gas. - d. Element III is a metal that forms a stable binary halide of the formula AX₂.

To solve the problem, we need to analyze the given ionization energies (IE) for the four elements and determine which element corresponds to each of the categories: reactive metal, reactive non-metal, noble gas, and a metal that forms a stable binary halide of the formula AX₂. ### Step-by-Step Solution: 1. **Understanding Ionization Energies:** - Ionization energy is the energy required to remove an electron from an atom. The first ionization energy (IE₁) is the energy needed to remove the first electron, and the second ionization energy (IE₂) is for removing the second electron. - A large jump in ionization energy between IE₁ and IE₂ indicates that after the removal of the first electron, the atom achieves a stable electron configuration (like that of a noble gas). ...
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