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In the correct Lewis dot structure of CO...

In the correct Lewis dot structure of `CO_(2)`, the total number of lone pairs are :

A

`:overset(..)(O)::C::overset(..)(O):`

B

`:underset(..)overset(..)(O):overset(..)(C)::overset(..)(O):`

C

`:overset(..)(O)::C:underset(..)overset(..)(O):`

D

`:underset(..)overset(..)(O):C:underset(..)overset(..)(O):`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the total number of lone pairs in the Lewis dot structure of carbon dioxide (CO₂), we can follow these steps: ### Step 1: Determine the valence electrons - Carbon (C) has 4 valence electrons. - Each oxygen (O) has 6 valence electrons. Since there are two oxygen atoms, we have 2 × 6 = 12 valence electrons from oxygen. **Total valence electrons = 4 (from C) + 12 (from O) = 16 valence electrons.** **Hint:** Remember to count the valence electrons for each atom based on its group number in the periodic table. ### Step 2: Draw the skeletal structure - Place the carbon atom in the center and the two oxygen atoms on either side. This gives us a skeletal structure of O-C-O. **Hint:** The central atom is usually the least electronegative element, which in this case is carbon. ### Step 3: Form bonds between the atoms - Connect the carbon atom to each oxygen atom with a single bond initially. This uses 4 of the 16 valence electrons (2 electrons per bond). - Now we have 16 - 4 = 12 valence electrons remaining. **Hint:** Each bond consists of 2 electrons. ### Step 4: Distribute remaining electrons to complete octets - Place the remaining 12 electrons around the oxygen atoms to satisfy the octet rule. Each oxygen needs 8 electrons in total. - Start by placing 6 electrons (3 lone pairs) around each oxygen atom. This uses up all 12 remaining electrons. **Hint:** Each oxygen atom can hold a maximum of 8 electrons, including those in bonds. ### Step 5: Check the structure - After placing the lone pairs, we notice that each oxygen has 6 electrons (3 lone pairs) and is connected to carbon with a single bond (2 electrons). This gives each oxygen a total of 8 electrons. - However, to minimize formal charges, we can convert one lone pair from each oxygen into a double bond with carbon. This results in a double bond between carbon and each oxygen, leading to the final structure of O=C=O. **Hint:** Double bonds can help satisfy the octet rule while minimizing formal charges. ### Step 6: Count the lone pairs - In the final structure (O=C=O), each oxygen atom has 2 lone pairs (4 electrons total). - Therefore, the total number of lone pairs in CO₂ is 2 (from one oxygen) + 2 (from the other oxygen) = 4 lone pairs. **Final Answer:** The total number of lone pairs in the Lewis dot structure of CO₂ is **4**. ### Summary of Steps: 1. Count valence electrons. 2. Draw the skeletal structure. 3. Form initial bonds. 4. Distribute remaining electrons. 5. Adjust bonds to minimize formal charges. 6. Count the lone pairs.
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