Which has the strongest bond?

Options

A. F - O
B. O - Cl
C. N - H
D. O - H

Answer

To determine which bond is the strongest among the given options (F-O, O-Cl, N-H, and O-H), we need to analyze the electronegativity of the elements involved in each bond. Here’s a step-by-step solution:

### Step 1: List the Electronegativity Values
First, we need to know the electronegativity values of the elements involved:
- Fluorine (F): 4.0
- Oxygen (O): 3.5
- Nitrogen (N): 3.0
- Chlorine (Cl): 3.0
- Hydrogen (H): 2.1

### Step 2: Determine the Electronegativity Differences
Next, we calculate the electronegativity differences for each bond:
1. **F-O**: |4.0 - 3.5| = 0.5
2. **O-Cl**: |3.5 - 3.0| = 0.5
3. **N-H**: |3.0 - 2.1| = 0.9
4. **O-H**: |3.5 - 2.1| = 1.4

### Step 3: Analyze the Electronegativity Differences
The bond strength is influenced by the difference in electronegativity:
- A larger electronegativity difference generally indicates a stronger bond due to increased ionic character.

### Step 4: Compare the Results
From our calculations:
- F-O: 0.5 (weak bond)
- O-Cl: 0.5 (weak bond)
- N-H: 0.9 (moderate bond)
- O-H: 1.4 (strong bond)

### Step 5: Conclusion
The bond with the highest electronegativity difference is the O-H bond, which indicates that it is the strongest bond among the options provided.

### Final Answer
The strongest bond is **O-H**.

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