Match the bond enthalpies given in column II with the molecules given in column I and mark the appropriate choice.
`{:(,"Column I",,"Column II "),((A),"Hydrogen "(H_(2)),(i),498.0 " kJ mol"^(-1)),((B),"Oxygen"(O_(2)),(ii),946.0" kJ mol"^(-1)),((C),"Nitrogen"(N_(2)),(iii),435.8 " kJ mol"^(-1)):}`

Options

A. `(A)to(i), (B)to(ii), (C) to (iii)`
B. `(A) to (iii), (B) to (ii), (C ) to (i) `
C. `(A) to (i), (B) to (iii), (C ) to (ii)`
D. `(A) to (iii), (B) to (i), (C ) to (ii)`

Explanation

To solve the problem of matching the bond enthalpies with the corresponding molecules, we can follow these steps:

### Step 1: Understand Bond Enthalpy
Bond enthalpy (or bond energy) is defined as the amount of energy required to break one mole of a specific type of bond in a molecule. The stronger the bond, the higher the bond enthalpy.

### Step 2: Analyze the Molecules in Column I
- **A: Hydrogen (H₂)** - Contains a single bond between two hydrogen atoms.
- **B: Oxygen (O₂)** - Contains a double bond between two oxygen atoms.
- **C: Nitrogen (N₂)** - Contains a triple bond between two nitrogen atoms.

### Step 3: Analyze the Bond Enthalpies in Column II
- **i: 498.0 kJ mol⁻¹**
- **ii: 946.0 kJ mol⁻¹**
- **iii: 435.8 kJ mol⁻¹**

### Step 4: Compare the Strength of Bonds
- Single bonds (like in H₂) are the weakest.
- Double bonds (like in O₂) are stronger than single bonds but weaker than triple bonds.
- Triple bonds (like in N₂) are the strongest.

### Step 5: Match the Bond Enthalpies
1. **Hydrogen (H₂)** has the weakest bond (single bond), so it will correspond to the lowest bond enthalpy. Thus, it matches with **(iii) 435.8 kJ mol⁻¹**.
2. **Oxygen (O₂)** has a double bond, which is stronger than a single bond but weaker than a triple bond. It matches with **(i) 498.0 kJ mol⁻¹**.
3. **Nitrogen (N₂)** has the strongest bond (triple bond), so it corresponds to the highest bond enthalpy. Thus, it matches with **(ii) 946.0 kJ mol⁻¹**.

### Final Matches
- A (H₂) - iii (435.8 kJ mol⁻¹)
- B (O₂) - i (498.0 kJ mol⁻¹)
- C (N₂) - ii (946.0 kJ mol⁻¹)

### Conclusion
The correct matching is:
- A → iii
- B → i
- C → ii