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Which type of hybridisation is shown by ...

Which type of hybridisation is shown by carbon atoms from left to right in the given compound :
` CH_(2) = CH - C -= N`?

A

`sp^(2),sp^(2),sp`

B

`sp^(2),sp,sp`

C

`sp,sp^(2),sp`

D

`sp^(3),sp^(2),sp`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the type of hybridization shown by the carbon atoms in the compound \( CH_2=CH-C \equiv N \), we will follow these steps: ### Step 1: Draw the Structure First, we need to draw the structure of the compound clearly. The compound consists of: - A carbon-carbon double bond between the first two carbon atoms. - A carbon-carbon single bond between the second carbon and the third carbon. - A carbon-nitrogen triple bond between the third carbon and the nitrogen atom. The structure can be represented as follows: ``` H H \ / C || C | C ≡ N ``` ### Step 2: Identify Each Carbon Atom Now, we will label each carbon atom in the structure: 1. The first carbon (C1) is connected to two hydrogen atoms and one carbon atom (C2) via a double bond. 2. The second carbon (C2) is connected to one hydrogen atom and two carbon atoms (C1 and C3). 3. The third carbon (C3) is connected to one carbon atom (C2) and one nitrogen atom (N) via a triple bond. ### Step 3: Count Sigma Bonds for Each Carbon Atom Next, we will count the number of sigma bonds for each carbon atom: - **C1**: Forms 3 sigma bonds (2 with H and 1 with C2). - **C2**: Forms 3 sigma bonds (1 with H, 1 with C1, and 1 with C3). - **C3**: Forms 2 sigma bonds (1 with C2 and 1 with N). ### Step 4: Determine Hybridization To determine the hybridization of each carbon atom, we use the formula: \[ \text{Hybridization} = \text{Number of sigma bonds} + \text{Number of lone pairs} \] - **C1**: 3 sigma bonds + 0 lone pairs = 3 → Hybridization: **sp²** - **C2**: 3 sigma bonds + 0 lone pairs = 3 → Hybridization: **sp²** - **C3**: 2 sigma bonds + 0 lone pairs = 2 → Hybridization: **sp** ### Conclusion From left to right, the hybridization of the carbon atoms in the compound \( CH_2=CH-C \equiv N \) is: - C1: sp² - C2: sp² - C3: sp Thus, the answer is: **sp², sp², sp**

To determine the type of hybridization shown by the carbon atoms in the compound \( CH_2=CH-C \equiv N \), we will follow these steps: ### Step 1: Draw the Structure First, we need to draw the structure of the compound clearly. The compound consists of: - A carbon-carbon double bond between the first two carbon atoms. - A carbon-carbon single bond between the second carbon and the third carbon. - A carbon-nitrogen triple bond between the third carbon and the nitrogen atom. ...
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