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Among the following molecules : SO(2),SF...

Among the following molecules : `SO_(2),SF_(4) ,CIF_(3) ,BrF_(5)` , and `XeF_(4)` , which of the following shapes does not describe any of the molecules mentioned ?

A

Bent

B

Trigonal Bipyramidal

C

See-Saw

D

T-Shape

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The correct Answer is:
To determine which shape does not describe any of the given molecules (SO₂, SF₄, ClF₃, BrF₅, and XeF₄), we will analyze the molecular geometry of each compound step by step. ### Step 1: Analyze SO₂ - **Valence Electrons**: Sulfur (S) has 6 valence electrons, and each Oxygen (O) has 6 valence electrons. - **Hybridization Calculation**: \[ \text{Hybridization} = \frac{1}{2} \left( \text{Number of valence electrons on S} + \text{Number of monovalent atoms} + \text{Charge} \right) \] \[ = \frac{1}{2} (6 + 0 + 0) = 3 \quad \text{(sp² hybridization)} \] - **Shape**: SO₂ has 2 bond pairs and 1 lone pair, giving it a bent shape. ### Step 2: Analyze SF₄ - **Valence Electrons**: Sulfur has 6, and each Fluorine (F) has 7 valence electrons. - **Hybridization Calculation**: \[ = \frac{1}{2} (6 + 4 + 0) = 5 \quad \text{(sp³d hybridization)} \] - **Shape**: SF₄ has 4 bond pairs and 1 lone pair, resulting in a seesaw shape. ### Step 3: Analyze ClF₃ - **Valence Electrons**: Chlorine has 7, and each Fluorine has 7. - **Hybridization Calculation**: \[ = \frac{1}{2} (7 + 3 + 0) = 5 \quad \text{(sp³d hybridization)} \] - **Shape**: ClF₃ has 3 bond pairs and 2 lone pairs, resulting in a T-shaped geometry. ### Step 4: Analyze BrF₅ - **Valence Electrons**: Bromine has 7, and each Fluorine has 7. - **Hybridization Calculation**: \[ = \frac{1}{2} (7 + 5 + 0) = 6 \quad \text{(sp³d² hybridization)} \] - **Shape**: BrF₅ has 5 bond pairs and 1 lone pair, resulting in a square pyramidal shape. ### Step 5: Analyze XeF₄ - **Valence Electrons**: Xenon has 8, and each Fluorine has 7. - **Hybridization Calculation**: \[ = \frac{1}{2} (8 + 4 + 0) = 6 \quad \text{(sp³d² hybridization)} \] - **Shape**: XeF₄ has 4 bond pairs and 2 lone pairs, resulting in a square planar shape. ### Conclusion Now that we have analyzed the shapes: - **Shapes Obtained**: - SO₂: Bent - SF₄: Seesaw - ClF₃: T-shaped - BrF₅: Square pyramidal - XeF₄: Square planar The shapes that were derived from the molecules are bent, seesaw, T-shaped, square pyramidal, and square planar. However, we did not derive a **trigonal bipyramidal** shape from any of the given molecules. ### Final Answer **The shape that does not describe any of the molecules mentioned is: Trigonal bipyramidal.**

To determine which shape does not describe any of the given molecules (SO₂, SF₄, ClF₃, BrF₅, and XeF₄), we will analyze the molecular geometry of each compound step by step. ### Step 1: Analyze SO₂ - **Valence Electrons**: Sulfur (S) has 6 valence electrons, and each Oxygen (O) has 6 valence electrons. - **Hybridization Calculation**: \[ \text{Hybridization} = \frac{1}{2} \left( \text{Number of valence electrons on S} + \text{Number of monovalent atoms} + \text{Charge} \right) \] ...
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