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Arrange in increasing order of s charact...

Arrange in increasing order of s character

A

`sp^(3) lt sp^(2) lt sp`

B

`sp lt sp^(2) lt sp^(3)`

C

`sp^(2) lt sp lt sp^(3)`

D

`sp^(2) lt sp^(3) lt sp`

Text Solution

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The correct Answer is:
To arrange the hybridizations sp3, sp2, and sp in increasing order of s character, we will calculate the s character percentage for each type of hybridization. ### Step-by-Step Solution: 1. **Understanding Hybridization**: - **sp3 Hybridization**: Involves 1 s orbital and 3 p orbitals. - **sp2 Hybridization**: Involves 1 s orbital and 2 p orbitals. - **sp Hybridization**: Involves 1 s orbital and 1 p orbital. 2. **Calculating s Character**: - The formula to calculate the s character percentage is: \[ \text{s character} = \left( \frac{\text{Number of s orbitals}}{\text{Total number of orbitals}} \right) \times 100 \] 3. **Calculating for sp3**: - Number of s orbitals = 1 - Total number of orbitals = 1 s + 3 p = 4 - s character = \( \left( \frac{1}{4} \right) \times 100 = 25\% \) 4. **Calculating for sp2**: - Number of s orbitals = 1 - Total number of orbitals = 1 s + 2 p = 3 - s character = \( \left( \frac{1}{3} \right) \times 100 \approx 33.33\% \) 5. **Calculating for sp**: - Number of s orbitals = 1 - Total number of orbitals = 1 s + 1 p = 2 - s character = \( \left( \frac{1}{2} \right) \times 100 = 50\% \) 6. **Arranging in Increasing Order**: - From the calculations: - sp3: 25% s character - sp2: 33.33% s character - sp: 50% s character - Therefore, the increasing order of s character is: \[ \text{sp3} < \text{sp2} < \text{sp} \] ### Final Answer: The increasing order of s character is: **sp3 < sp2 < sp**

To arrange the hybridizations sp3, sp2, and sp in increasing order of s character, we will calculate the s character percentage for each type of hybridization. ### Step-by-Step Solution: 1. **Understanding Hybridization**: - **sp3 Hybridization**: Involves 1 s orbital and 3 p orbitals. - **sp2 Hybridization**: Involves 1 s orbital and 2 p orbitals. - **sp Hybridization**: Involves 1 s orbital and 1 p orbital. ...
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NCERT FINGERTIPS ENGLISH-CHEMICAL BONDING & MOLECULAR STRUCTURE-Assertion And Reason
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  5. Assertion : PF(5),SF(6)and H(2)SO(4) are the examples of expanded octe...

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  6. Assertion : Octet rule is based upon the chemical inertness of noble g...

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  7. Assertion : Sodium chloride (NaCl) is a stable ionic solid. Reason ...

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  9. Assertion : The experimentally determined carbon to oxygen bond length...

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  10. Assertion : The dipole moment in case of BeF(2) is zero. Reason : T...

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  13. Assertion : In NH(3), N "is " sp^(3) hybridised but bond angle is 107^...

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  14. Ionic bonds are non-directional while covalent bonds are directional.

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  15. Assertion : O(2) molecule is diamagnetic while C(2) molecule is parama...

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