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According to molecular orbital theory, w...

According to molecular orbital theory, which of the following will not be a viable molecule?

A

`H_(2)^(+)`

B

`Be_(2)`

C

`B_(2)`

D

`C_(2)`

Text Solution

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The correct Answer is:
To determine which of the given molecules will not be viable according to molecular orbital theory, we will follow these steps: ### Step 1: Identify the number of electrons in each molecule. - **H2+**: Each hydrogen atom has 1 electron. For H2, there are 2 electrons, but since there is a positive charge, H2+ has 1 electron. - **Be2**: Each beryllium atom has 4 electrons. Therefore, Be2 has a total of 8 electrons. - **B2**: Each boron atom has 5 electrons. Thus, B2 has a total of 10 electrons. - **C2**: Each carbon atom has 6 electrons. Therefore, C2 has a total of 12 electrons. ### Step 2: Construct the molecular orbital diagram for each molecule. The molecular orbital energy levels are arranged as follows: - σ 1s - σ* 1s - σ 2s - σ* 2s - σ 2px - σ 2py - σ 2pz ### Step 3: Fill the molecular orbitals with the electrons for each molecule and calculate the bond order. 1. **H2+** (1 electron): - Fill the molecular orbitals: σ 1s (1 electron). - Bonding electrons = 1, Anti-bonding electrons = 0. - Bond order (BO) = (Bonding - Anti-bonding) / 2 = (1 - 0) / 2 = 0.5. - Since BO > 0, H2+ exists. 2. **Be2** (8 electrons): - Fill the molecular orbitals: σ 1s (2), σ* 1s (2), σ 2s (2), σ* 2s (2). - Bonding electrons = 4, Anti-bonding electrons = 4. - Bond order (BO) = (4 - 4) / 2 = 0. - Since BO = 0, Be2 does not exist. 3. **B2** (10 electrons): - Fill the molecular orbitals: σ 1s (2), σ* 1s (2), σ 2s (2), σ* 2s (2), σ 2px (2). - Bonding electrons = 6, Anti-bonding electrons = 4. - Bond order (BO) = (6 - 4) / 2 = 1. - Since BO > 0, B2 exists. 4. **C2** (12 electrons): - Fill the molecular orbitals: σ 1s (2), σ* 1s (2), σ 2s (2), σ* 2s (2), σ 2px (2), σ 2py (2). - Bonding electrons = 8, Anti-bonding electrons = 4. - Bond order (BO) = (8 - 4) / 2 = 2. - Since BO > 0, C2 exists. ### Conclusion: Based on the calculations, the molecule that does not exist according to molecular orbital theory is **Be2**. ### Final Answer: **Be2 will not be a viable molecule.** ---

To determine which of the given molecules will not be viable according to molecular orbital theory, we will follow these steps: ### Step 1: Identify the number of electrons in each molecule. - **H2+**: Each hydrogen atom has 1 electron. For H2, there are 2 electrons, but since there is a positive charge, H2+ has 1 electron. - **Be2**: Each beryllium atom has 4 electrons. Therefore, Be2 has a total of 8 electrons. - **B2**: Each boron atom has 5 electrons. Thus, B2 has a total of 10 electrons. - **C2**: Each carbon atom has 6 electrons. Therefore, C2 has a total of 12 electrons. ...
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L.C.A.O. Principle is involved in the formation of the molecular orbitals according to molecular orbital theory. The energy of the bonding molecular orbital is less than that of the combining atomic orbitals while that of the antibonding molecular orbitals while that of the order (B.O.)=1/2(N_(b)-N_(a)) helps in predicting (i) formation of molecules/molecular ions, bond dissociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic orbitals at the time of overlap must have the same symmetry as well. In the homonuclear molecule which of the following sets of M.O. orbitals are degenerate ?

L.C.A.O. Principle is involved in the formation of the molecular orbitals according to molecular orbital theory. The energy of the bonding molecular orbital is less than that of the combining atomic orbitals while that of the antibonding molecular orbitals while that of the order (B.O.)=1/2(N_(b)-N_(a)) helps in predicting (i) formation of molecules/molecular ions, bond dissociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic orbitals at the time of overlap must have the same symmetry as well. The bond order (B.O.) in B_(2) molecule is:

L.C.A.O. Principle is involved in the formation of the molecular orbitals according to molecular orbital theory. The energy of the bonding molecular orbital is less than that of the combining atomic orbitals while that of the antibonding molecular orbitals while that of the order (B.O.)=1/2(N_(b)-N_(a)) helps in predicting formation of molecules/molecular ions, bond dissociation energy, stability and bond length. Only the molecules or ions with positive B.O. can be formed. These will be diamagnetic if all molecular orbitals are dilled and paramagnetic if one of more are half filled. The atomic orbitals at the time of overlap must have the same symmetry as well. In the formation of N_(2)^(+) from N_(2), the electron is removed from a

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