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Consider the following molecules under...

Consider the following molecules
`underset(I)(O_(2)),O_(2)underset(II)(("AsF"_(6))),underset(III)(KO_(2))`
Choose the correct answer.

A

The correct decreasing bond order is `II gt I gt III`.

B

The correct decreasing order of bond length is `III gt II gt I`.

C

The bond strength of I is less than that of III.

D

Bond dissociation energy is highest in case of III.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the bond order of the given molecules \(O_2\), \(AsF_6\), and \(KO_2\), we will analyze each molecule step by step. ### Step 1: Understanding Bond Order Bond order is defined as the number of chemical bonds between a pair of atoms. It can be calculated using the formula: \[ \text{Bond Order} = \frac{(\text{Number of bonding electrons} - \text{Number of antibonding electrons})}{2} \] Higher bond order indicates stronger bonds. ### Step 2: Analyzing \(O_2\) For molecular oxygen (\(O_2\)): - It has a total of 16 electrons. - The molecular orbital configuration is: \(\sigma_{1s}^2 \sigma_{1s}^*^2 \sigma_{2s}^2 \sigma_{2s}^*^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^*^1 \pi_{2p_y}^*^1\). - Bond order calculation: \[ \text{Bond Order of } O_2 = \frac{(10 - 6)}{2} = 2 \] ### Step 3: Analyzing \(AsF_6\) For \(AsF_6\): - In this case, \(AsF_6\) can be viewed as a complex where the \(O_2\) is present as \(O_2^+\). - The bond order for \(O_2^+\) is calculated similarly: \[ \text{Bond Order of } O_2^+ = \frac{(10 - 5)}{2} = 2.5 \] ### Step 4: Analyzing \(KO_2\) For potassium superoxide (\(KO_2\)): - In \(KO_2\), the \(O_2\) exists as \(O_2^-\). - The bond order for \(O_2^-\) is: \[ \text{Bond Order of } O_2^- = \frac{(10 - 7)}{2} = 1.5 \] ### Step 5: Comparing Bond Orders Now we can summarize the bond orders: - \(O_2\) has a bond order of 2. - \(AsF_6\) (as \(O_2^+\)) has a bond order of 2.5. - \(KO_2\) (as \(O_2^-\)) has a bond order of 1.5. ### Step 6: Conclusion The decreasing order of bond strength (and hence bond order) is: \[ AsF_6 > O_2 > KO_2 \] Thus, the correct answer is option A: \(AsF_6\) (II), \(O_2\) (I), \(KO_2\) (III).

To solve the question regarding the bond order of the given molecules \(O_2\), \(AsF_6\), and \(KO_2\), we will analyze each molecule step by step. ### Step 1: Understanding Bond Order Bond order is defined as the number of chemical bonds between a pair of atoms. It can be calculated using the formula: \[ \text{Bond Order} = \frac{(\text{Number of bonding electrons} - \text{Number of antibonding electrons})}{2} \] Higher bond order indicates stronger bonds. ...
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