In which of the following molecule/ion all the bonds are not equal? A` XeF_(4)` B `BF_(4)^(-)` C `C_(2)H_(4)` D `SiF_(4)`

Options

A. `XeF_(4)`
B. `BF_(4)^(-)`
C. `C_(2)H_(4)`
D. `SiF_(4)`

Explanation

To determine which of the given molecules/ions has bonds that are not equal, we will analyze each option step by step.

### Step 1: Analyze XeF4
- **Structure**: Xenon tetrafluoride (XeF4) has a square planar geometry.
- **Bond Types**: All the bonds in XeF4 are Xe-F single bonds.
- **Conclusion**: All bonds are equal.

### Step 2: Analyze BF4^(-)
- **Structure**: The tetrafluoroborate ion (BF4^(-)) has a tetrahedral geometry.
- **Bond Types**: All the bonds in BF4^(-) are B-F single bonds.
- **Conclusion**: All bonds are equal.

### Step 3: Analyze C2H4
- **Structure**: Ethylene (C2H4) has a planar structure.
- **Bond Types**: It contains one C=C double bond and four C-H single bonds. The C=C bond consists of one sigma (σ) bond and one pi (π) bond, while the C-H bonds are all sigma bonds.
- **Conclusion**: The C=C bond is different from the C-H bonds, hence not all bonds are equal.

### Step 4: Analyze SiF4
- **Structure**: Silicon tetrafluoride (SiF4) has a tetrahedral geometry.
- **Bond Types**: All the bonds in SiF4 are Si-F single bonds.
- **Conclusion**: All bonds are equal.

### Final Answer
Based on the analysis, the molecule where not all bonds are equal is **C (C2H4)**.