The volume occupied by 4.4 g of `CO_(2)` at STP is

Options

A. 22.4 L
B. 44.8 L
C. 12.2 L
D. 2.24 L

Explanation

To find the volume occupied by 4.4 g of CO₂ at STP, we can follow these steps:

### Step 1: Identify the given data
- Mass of CO₂ = 4.4 g
- Molar volume of a gas at STP = 22.4 L/mol

### Step 2: Calculate the molar mass of CO₂
The molar mass of CO₂ can be calculated using the atomic masses of carbon and oxygen:
- Atomic mass of Carbon (C) = 12 g/mol
- Atomic mass of Oxygen (O) = 16 g/mol

Since CO₂ has one carbon atom and two oxygen atoms, the molar mass can be calculated as follows:
\[ \text{Molar mass of CO₂} = 12 + (2 \times 16) = 12 + 32 = 44 \text{ g/mol} \]

### Step 3: Calculate the number of moles of CO₂
Using the formula for the number of moles:
\[ \text{Number of moles (n)} = \frac{\text{mass}}{\text{molar mass}} \]
Substituting the values:
\[ n = \frac{4.4 \text{ g}}{44 \text{ g/mol}} = 0.1 \text{ mol} \]

### Step 4: Calculate the volume of CO₂ at STP
Using the relationship between volume, number of moles, and molar volume:
\[ \text{Volume} = n \times \text{molar volume} \]
Substituting the values:
\[ \text{Volume} = 0.1 \text{ mol} \times 22.4 \text{ L/mol} = 2.24 \text{ L} \]

### Final Answer
The volume occupied by 4.4 g of CO₂ at STP is **2.24 L**.

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