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Which of the following expressions repre...

Which of the following expressions represents the value and unit of van der Waals constant a?

A

`a = (V)/(n) ," L mol"^(-1)`

B

`a = (PV)/(n) , "atm L"^(2) mol^(-1)`

C

`a = (PV^(2))/(n^(2)) , "atm L"^(2) mol^(-1)`

D

`a = (P)/(n) ," atm mol"^(-1)`

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AI Generated Solution

The correct Answer is:
To solve the question regarding the van der Waals constant \( a \), we will follow these steps: ### Step 1: Understand the van der Waals equation The van der Waals equation for real gases is given by: \[ \left(P + \frac{a}{V_m^2}\right)(V_m - b) = RT \] where: - \( P \) = pressure of the gas - \( V_m \) = molar volume of the gas - \( T \) = temperature - \( R \) = universal gas constant - \( a \) = van der Waals constant for the attractive forces between particles - \( b \) = volume occupied by the gas particles ### Step 2: Rearranging the equation From the van der Waals equation, we can isolate the term involving \( a \): \[ P = \frac{RT}{V_m - b} - \frac{a}{V_m^2} \] This shows that \( a \) is related to the pressure and volume of the gas. ### Step 3: Identify the units of \( a \) To find the units of \( a \), we can look at the term \( \frac{a}{V_m^2} \). The units of pressure \( P \) are typically in atmospheres (atm), and the units of molar volume \( V_m \) are in liters per mole (L/mol). Thus, we can express the units of \( a \) as follows: - Rearranging gives us \( a = P \cdot V_m^2 \). - The units of pressure \( P \) are atm, and the units of molar volume \( V_m \) are L/mol. ### Step 4: Calculate the units of \( a \) Substituting the units into the equation: \[ \text{Units of } a = \text{atm} \cdot \left(\frac{\text{L}}{\text{mol}}\right)^2 = \text{atm} \cdot \frac{\text{L}^2}{\text{mol}^2} \] Thus, the units of \( a \) are: \[ \text{Units of } a = \text{atm} \cdot \text{L}^2 \cdot \text{mol}^{-2} \] ### Step 5: Conclusion The expression representing the value and unit of the van der Waals constant \( a \) is: \[ \frac{P \cdot V^2}{n^2} \quad \text{with units } \text{atm} \cdot \text{L}^2 \cdot \text{mol}^{-2} \] ### Final Answer The correct option is: \[ \text{Option C: } \frac{P}{V^2} \cdot n^{-2} \text{ with units } \text{atm} \cdot \text{L}^2 \cdot \text{mol}^{-2} \]
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