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Two reactions are given below : (i) C...

Two reactions are given below :
(i) `CO_((g))+(1)/(2)O_(2(g))rarrCO_(2(g))`
(ii) `Ag_(2)O_((s)) rarr 2Ag_((s))+(1)/(2)O_(2(g))`
Which of the following statements is true ?

A

For (i) `DeltaH lt DeltaU` and for (ii) `DeltaH gt DeltaU`

B

For (i) `DeltaH gt DeltaU` and for (ii) `DeltaH lt DeltaU`

C

For both (i) and (ii) `DeltaH gt DeltaU`

D

For both (i) and (ii) `DeltaH lt DeltaU`

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The correct Answer is:
To determine the correct relationship between ΔH (enthalpy change) and ΔU (internal energy change) for the given reactions, we will use the equation: \[ \Delta H = \Delta U + n_g RT \] where \(n_g\) is the change in the number of moles of gas, \(R\) is the universal gas constant, and \(T\) is the temperature in Kelvin. ### Step 1: Analyze Reaction 1 The first reaction is: \[ CO_{(g)} + \frac{1}{2} O_{2(g)} \rightarrow CO_{2(g)} \] **Calculate \(n_g\)**: - **Products**: 1 mole of \(CO_2\) (gaseous) - **Reactants**: 1 mole of \(CO\) + \(\frac{1}{2}\) mole of \(O_2\) = \(1 + \frac{1}{2} = \frac{3}{2}\) moles of gas Thus, \[ n_g = \text{moles of products} - \text{moles of reactants} = 1 - \frac{3}{2} = -\frac{1}{2} \] **Substituting into the equation**: \[ \Delta H = \Delta U + \left(-\frac{1}{2}\right) RT \] This implies: \[ \Delta H = \Delta U - \frac{1}{2} RT \] From this, we can conclude: \[ \Delta H < \Delta U \] ### Step 2: Analyze Reaction 2 The second reaction is: \[ Ag_2O_{(s)} \rightarrow 2Ag_{(s)} + \frac{1}{2} O_{2(g)} \] **Calculate \(n_g\)**: - **Products**: \(\frac{1}{2}\) mole of \(O_2\) (gaseous) - **Reactants**: 0 moles of gas (since \(Ag_2O\) is solid) Thus, \[ n_g = \text{moles of products} - \text{moles of reactants} = \frac{1}{2} - 0 = \frac{1}{2} \] **Substituting into the equation**: \[ \Delta H = \Delta U + \left(\frac{1}{2}\right) RT \] This implies: \[ \Delta H = \Delta U + \frac{1}{2} RT \] From this, we can conclude: \[ \Delta H > \Delta U \] ### Conclusion For the two reactions, we have determined: 1. For Reaction 1: \(\Delta H < \Delta U\) 2. For Reaction 2: \(\Delta H > \Delta U\) Thus, the correct statement is: **Option A**: For Reaction 1, \(\Delta H\) is less than \(\Delta U\) and for Reaction 2, \(\Delta H\) is greater than \(\Delta U\).

To determine the correct relationship between ΔH (enthalpy change) and ΔU (internal energy change) for the given reactions, we will use the equation: \[ \Delta H = \Delta U + n_g RT \] where \(n_g\) is the change in the number of moles of gas, \(R\) is the universal gas constant, and \(T\) is the temperature in Kelvin. ...
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