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For combustion of 1 mole of benzene at 2...

For combustion of 1 mole of benzene at `25^(@)C`, the heat of reaction at constant pressure is `-780.9" kcal."`
What will be the heat of reaction at constant volume ?
`C_(6)H_(6(l))+7(1)/(2)O_(2(g))rarr 6CO_(2(g))+3H_(2)O_((l))`

A

`-781.8" kcal"`

B

`-"780.0 kcal"`

C

`+"781.8 kcal"`

D

`+"780.0 kcal"`

Text Solution

Verified by Experts

The correct Answer is:
B
`q_(p)=q_(v)+Deltan_(g)RT, q_(v)=q_(p)-Deltan_(g)RT(DeltaH=DeltaU+Deltan_(g)RT)`
`q_(v)=-780.9-(-1.5xx2xx298xx10^(-3))=-"780 kcal"`
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