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PCl(5),PCl(3)andCl(2) are at equilibrium...

`PCl_(5),PCl_(3)andCl_(2)` are at equilibrium at 500 K with concentration `2.1 M` `PCl_(3)`, `2.1 M` `Cl_(2)` and `1.9 M` `PCl_(5)`.
The equilibrium constant for the given reaction is
`PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))`

A

(a) 2.32

B

(b) 1.79

C

(c) 4.2

D

(d) 3.8

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(c)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(2.1xx2.1)/(1.9)=2.32`
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