18.4 g of `N_(2)O_(4)` is taken in a 1 L closed vessel and heated till the equilibrium is reached.
`N_(2)O_(4(g))hArr2NO_(2(g))`
At equilibrium it is found that 50% of `N_(2)O_(4)` is dissociated . What will be the value of equilibrium constant?

Options

A. (a) 0.2
B. (b) 2
C. (c) 0.4
D. (d) 0.8

Answer

C

Explanation

`{:(,N_(2)O_(4(g)),hArr,2NO_(2(g))),("Intial conc.",18.4,,0),("No. of moles",(18.4)/(92)=0.2,,),("At equilibrium",0.2-0.1,,2xx0.1),(,=0.1,,=0.2):}`
`K_(c)=(0.2xx0.2)/(0.1)=0.4`