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The reaction 2SO(2)+2O(2)hArr 2SO(3) wil...

The reaction `2SO_(2)+2O_(2)hArr 2SO_(3)` will be favoured by

A

a. high temperature and low pressure

B

b. low temperature and high pressure

C

c. high temperature and high pressure

D

d. low temperature and low pressure.

Text Solution

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The correct Answer is:
To determine the conditions under which the reaction \(2SO_2 + 2O_2 \rightleftharpoons 2SO_3\) will be favored, we can analyze the reaction based on Le Chatelier's principle, which states that if a system at equilibrium is subjected to a change in conditions, the system will adjust to counteract that change and restore a new equilibrium. ### Step-by-Step Solution: 1. **Identify the Reaction Type**: The given reaction is \(2SO_2 + 2O_2 \rightleftharpoons 2SO_3\). This is an oxidation reaction where sulfur dioxide (\(SO_2\)) is converted to sulfur trioxide (\(SO_3\)). **Hint**: Recognize the nature of the reaction (oxidation) and its products. 2. **Count the Moles of Reactants and Products**: - Reactants: \(2SO_2 + 2O_2\) = 4 moles - Products: \(2SO_3\) = 2 moles There is a decrease in the number of moles from 4 to 2. **Hint**: Always count the moles of reactants and products to understand how changes in pressure will affect the equilibrium. 3. **Determine the Reaction's Heat Change**: This reaction is exothermic, meaning it releases heat. In exothermic reactions, heat can be considered as a product. **Hint**: Remember that exothermic reactions release heat, which can influence equilibrium. 4. **Apply Le Chatelier's Principle**: - **Temperature**: For exothermic reactions, lowering the temperature favors the formation of products (in this case, \(SO_3\)). - **Pressure**: Increasing the pressure favors the side of the reaction with fewer moles of gas. Since the products have fewer moles (2 moles of \(SO_3\)) compared to the reactants (4 moles), increasing the pressure will also favor the formation of \(SO_3\). **Hint**: Use Le Chatelier's principle to analyze how temperature and pressure changes affect the equilibrium. 5. **Conclusion**: The reaction \(2SO_2 + 2O_2 \rightleftharpoons 2SO_3\) will be favored by low temperature and high pressure. **Final Answer**: The correct option is **low temperature and high pressure**.

To determine the conditions under which the reaction \(2SO_2 + 2O_2 \rightleftharpoons 2SO_3\) will be favored, we can analyze the reaction based on Le Chatelier's principle, which states that if a system at equilibrium is subjected to a change in conditions, the system will adjust to counteract that change and restore a new equilibrium. ### Step-by-Step Solution: 1. **Identify the Reaction Type**: The given reaction is \(2SO_2 + 2O_2 \rightleftharpoons 2SO_3\). This is an oxidation reaction where sulfur dioxide (\(SO_2\)) is converted to sulfur trioxide (\(SO_3\)). **Hint**: Recognize the nature of the reaction (oxidation) and its products. ...
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