Dissociation constant of `CH_(3)COOH` and ` NH_(4)OH` in squeous solution are `10^(-5)` if pH of a `CH_(3)COOH` solution is 3, what will be the pH of `NH_(4)OH` ?

Options

A. `3.0`
B. `4.0`
C. `10.0`
D. `11.0`

Explanation

To solve the problem, we need to find the pH of the NH₄OH solution given the pH of the CH₃COOH solution and the fact that both have the same dissociation constant (Kₐ = K_b = 10⁻⁵).

### Step-by-Step Solution:

1. **Identify the given information:**
- The dissociation constant (Kₐ) of CH₃COOH is \(10^{-5}\).
- The pH of the CH₃COOH solution is 3.
- We need to find the pH of the NH₄OH solution.

2. **Calculate the pOH from the pH of CH₃COOH:**
- We know the relationship between pH and pOH:
\[ \text{pH} + \text{pOH} = 14 \]
- Given that pH = 3:
\[ \text{pOH} = 14 - \text{pH} = 14 - 3 = 11 \]

3. **Relate the pOH of NH₄OH to its pH:**
- Since we have calculated the pOH of the NH₄OH solution, we can now find its pH using the same relationship:
\[ \text{pH} + \text{pOH} = 14 \]
- Substituting the value of pOH:
\[ \text{pH} = 14 - \text{pOH} = 14 - 11 = 3 \]

4. **Conclusion:**
- The pH of the NH₄OH solution is 3.

### Final Answer:
The pH of the NH₄OH solution is 11.