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Predict if there will be any precipitate...

Predict if there will be any precipitate by mixing 50 mL of 0.01 M NaCl and 50 mL of 0.01 M `AgNO_(3)` solution. The solubility product of AgCl is `1.5xx10^(-10)`.

A

Since ionic product is greater than solubility product no precipitate will be formed.

B

Since ionic product is lesser than solubility product, precipitation will occur .

C

Since ionic product is greater than solubility product, precipitation will occur.

D

Since ionic product and solubility product are same, precipitation will not occur.

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The correct Answer is:
To determine if a precipitate will form when mixing 50 mL of 0.01 M NaCl and 50 mL of 0.01 M AgNO₃, we will follow these steps: ### Step 1: Calculate the number of moles of Cl⁻ and Ag⁺ ions 1. **For NaCl:** - Volume = 50 mL = 0.050 L - Concentration = 0.01 M - Moles of Cl⁻ = Volume × Concentration = 0.050 L × 0.01 mol/L = 0.0005 mol = 0.5 mmol 2. **For AgNO₃:** - Volume = 50 mL = 0.050 L - Concentration = 0.01 M - Moles of Ag⁺ = Volume × Concentration = 0.050 L × 0.01 mol/L = 0.0005 mol = 0.5 mmol ### Step 2: Calculate the total volume after mixing - Total volume = Volume of NaCl + Volume of AgNO₃ = 50 mL + 50 mL = 100 mL = 0.1 L ### Step 3: Calculate the concentrations of Cl⁻ and Ag⁺ in the mixed solution 1. **Concentration of Cl⁻:** - Concentration = Moles / Total Volume = 0.0005 mol / 0.1 L = 0.005 M 2. **Concentration of Ag⁺:** - Concentration = Moles / Total Volume = 0.0005 mol / 0.1 L = 0.005 M ### Step 4: Calculate the ionic product (IP) of AgCl - The ionic product (IP) is given by: \[ \text{IP} = [\text{Ag}^+] \times [\text{Cl}^-] = 0.005 \, \text{M} \times 0.005 \, \text{M} = 2.5 \times 10^{-5} \] ### Step 5: Compare the ionic product with the solubility product (Ksp) of AgCl - Given Ksp of AgCl = \(1.5 \times 10^{-10}\) - Since \( \text{IP} = 2.5 \times 10^{-5} \) is greater than \( Ksp = 1.5 \times 10^{-10} \), we conclude that the solution is supersaturated. ### Step 6: Conclusion - Because the ionic product is greater than the solubility product, a precipitate of AgCl will form when the two solutions are mixed. ### Final Answer - Yes, a precipitate will form. ---

To determine if a precipitate will form when mixing 50 mL of 0.01 M NaCl and 50 mL of 0.01 M AgNO₃, we will follow these steps: ### Step 1: Calculate the number of moles of Cl⁻ and Ag⁺ ions 1. **For NaCl:** - Volume = 50 mL = 0.050 L - Concentration = 0.01 M - Moles of Cl⁻ = Volume × Concentration = 0.050 L × 0.01 mol/L = 0.0005 mol = 0.5 mmol ...
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