The oxidation states of sulphur in the anions `SO_(3)^(2-), S_(2)O_(4)^(2-),SO_(4)^(2-)`, and `S_(2)O_(6)^(2-)` follow the order

Options

A. `S_(2)O_(4)^(2-)gtS_(2)O_(6)^(2-)gtSO_(4)^(2-)gtSO_(3)^(2-)`
B. `S_(2)O_(6)^(2-)gtSO_(3)^(2-)gtS_(2)O_(4)^(2-)gtSO_(4)^(2-)`
C. `SO_(4)^(2-) gt S_(2)O_(6)^(2-)gtSO_(3)^(2-)gtS_(2)O_(4)^(2-)`
D. `SO_(3)^(2-) gtSO_(4)^(2-)gtS_(2)O_(4)^(2-)gtS_(2)O_(6)^(2-)`

Explanation

To determine the oxidation states of sulfur in the anions \( SO_3^{2-}, S_2O_4^{2-}, SO_4^{2-}, \) and \( S_2O_6^{2-} \), we can follow these steps:

### Step 1: Determine the oxidation state of sulfur in \( SO_3^{2-} \)

1. Let the oxidation state of sulfur be \( x \).
2. The oxidation state of oxygen is \( -2 \).
3. The equation for the anion is:
\[ x + 3(-2) = -2 \]
4. Simplifying this gives:
\[ x - 6 = -2 \implies x = +4 \]

### Step 2: Determine the oxidation state of sulfur in \( S_2O_4^{2-} \)

1. Let the oxidation state of sulfur be \( x \).
2. The equation for the anion is:
\[ 2x + 4(-2) = -2 \]
3. Simplifying this gives:
\[ 2x - 8 = -2 \implies 2x = +6 \implies x = +3 \]

### Step 3: Determine the oxidation state of sulfur in \( SO_4^{2-} \)

1. Let the oxidation state of sulfur be \( x \).
2. The equation for the anion is:
\[ x + 4(-2) = -2 \]
3. Simplifying this gives:
\[ x - 8 = -2 \implies x = +6 \]

### Step 4: Determine the oxidation state of sulfur in \( S_2O_6^{2-} \)

1. Let the oxidation state of sulfur be \( x \).
2. The equation for the anion is:
\[ 2x + 6(-2) = -2 \]
3. Simplifying this gives:
\[ 2x - 12 = -2 \implies 2x = +10 \implies x = +5 \]

### Step 5: Summarize the oxidation states

- For \( SO_3^{2-} \): \( +4 \)
- For \( S_2O_4^{2-} \): \( +3 \)
- For \( SO_4^{2-} \): \( +6 \)
- For \( S_2O_6^{2-} \): \( +5 \)

### Step 6: Arrange in order of oxidation states

Now we can arrange the oxidation states of sulfur in the anions in decreasing order:
1. \( SO_4^{2-} \) (Oxidation state: +6)
2. \( S_2O_6^{2-} \) (Oxidation state: +5)
3. \( SO_3^{2-} \) (Oxidation state: +4)
4. \( S_2O_4^{2-} \) (Oxidation state: +3)

### Final Answer

The order of oxidation states of sulfur in the anions is:
\[ SO_4^{2-} > S_2O_6^{2-} > SO_3^{2-} > S_2O_4^{2-} \]