Match the compounds given in column I with oxidation states of carbon given in column II and mark the appropriate choice.
`{:(,"Column I",,"Column II"),("(A)",C_(6)H_(12)O_(6)," (i)"," +3"),("(B)",CHCl_(3)," (ii)"," -3"),("(C)",CH_(3)CH_(3)," (iii)"," +2"),("(D)",(CO OH)_(2)," (iv)"," 0"):}`

Options

A. (A) `rarr` (iv), (B) `rarr ` (iii), (C) `rarr` (ii), (D) `rarr` (i)
B. (A) `rarr` (i), (B) `rarr ` (ii), (C) `rarr` (iii), (D) `rarr` (iv)
C. (A) `rarr` (ii), (B) `rarr ` (iii), (C) `rarr` (iv), (D) `rarr` (i)
D. (A) `rarr` (iii), (B) `rarr ` (ii), (C) `rarr` (i), (D) `rarr` (iv)

Explanation

To solve the problem of matching the compounds in Column I with their respective oxidation states of carbon in Column II, we will calculate the oxidation state of carbon in each compound step by step.

### Step 1: Calculate the oxidation state of carbon in C₆H₁₂O₆ (Glucose)

1. **Let the oxidation state of carbon be \( x \)**.
2. The formula for glucose is C₆H₁₂O₆, which contains:
- 6 carbon atoms
- 12 hydrogen atoms
- 6 oxygen atoms
3. The equation for the oxidation state can be set up as follows:
\[ 6x + 12(1) + 6(-2) = 0 \]
Simplifying this gives:
\[ 6x + 12 - 12 = 0 \implies 6x = 0 \implies x = 0 \]
4. Therefore, the oxidation state of carbon in C₆H₁₂O₆ is **0**.

### Step 2: Calculate the oxidation state of carbon in CHCl₃ (Chloroform)

1. **Let the oxidation state of carbon be \( x \)**.
2. The formula for chloroform is CHCl₃, which contains:
- 1 carbon atom
- 1 hydrogen atom
- 3 chlorine atoms
3. The equation for the oxidation state can be set up as follows:
\[ x + 1(1) + 3(-1) = 0 \]
Simplifying this gives:
\[ x + 1 - 3 = 0 \implies x - 2 = 0 \implies x = +2 \]
4. Therefore, the oxidation state of carbon in CHCl₃ is **+2**.

### Step 3: Calculate the oxidation state of carbon in C₂H₆ (Ethane)

1. **Let the oxidation state of carbon be \( x \)**.
2. The formula for ethane is C₂H₆, which contains:
- 2 carbon atoms
- 6 hydrogen atoms
3. The equation for the oxidation state can be set up as follows:
\[ 2x + 6(1) = 0 \]
Simplifying this gives:
\[ 2x + 6 = 0 \implies 2x = -6 \implies x = -3 \]
4. Therefore, the oxidation state of carbon in C₂H₆ is **-3**.

### Step 4: Calculate the oxidation state of carbon in (COOH)₂ (Oxalic Acid)

1. **Let the oxidation state of carbon be \( x \)**.
2. The formula for oxalic acid is (COOH)₂, which can be rewritten as C₂O₄H₂, which contains:
- 2 carbon atoms
- 4 oxygen atoms
- 2 hydrogen atoms
3. The equation for the oxidation state can be set up as follows:
\[ 2x + 2(1) + 4(-2) = 0 \]
Simplifying this gives:
\[ 2x + 2 - 8 = 0 \implies 2x - 6 = 0 \implies 2x = 6 \implies x = +3 \]
4. Therefore, the oxidation state of carbon in (COOH)₂ is **+3**.

### Summary of Results
- (A) C₆H₁₂O₆ → 0 (matches with iv)
- (B) CHCl₃ → +2 (matches with iii)
- (C) C₂H₆ → -3 (matches with ii)
- (D) (COOH)₂ → +3 (matches with i)

### Final Matching
- A → iv (0)
- B → iii (+2)
- C → ii (-3)
- D → i (+3)