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Which compound amongst the following gas...

Which compound amongst the following gas the highest oxidation number of Mn?
`KMnO_(4), K_(2)MnO_(2), MnO_(2) and Mn_(2)O_(3)`

A

(A) `KMnO_(4)`

B

(B) `K_(2)MnO_(4)`

C

(C) `MnO_(2)`

D

(D) `Mn_(2)O_(3)`

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The correct Answer is:
To determine which compound has the highest oxidation number of manganese (Mn) among the given options, we will calculate the oxidation number of Mn in each compound step by step. ### Step 1: Calculate the oxidation number of Mn in KMnO₄ 1. The formula for potassium permanganate is KMnO₄. 2. The oxidation number of potassium (K) is +1. 3. The oxidation number of oxygen (O) is -2. 4. Let the oxidation number of Mn be \( x \). 5. The overall charge of the compound is neutral (0), so we can set up the equation: \[ +1 + x + 4(-2) = 0 \] 6. Simplifying this gives: \[ +1 + x - 8 = 0 \implies x - 7 = 0 \implies x = +7 \] ### Step 2: Calculate the oxidation number of Mn in K₂MnO₂ 1. The formula for potassium manganate is K₂MnO₂. 2. The oxidation number of potassium (K) is +1, and there are 2 potassium atoms, so: \[ 2(+1) = +2 \] 3. The oxidation number of oxygen (O) is -2, and there are 2 oxygen atoms, so: \[ 2(-2) = -4 \] 4. Let the oxidation number of Mn be \( x \). 5. Setting up the equation: \[ +2 + x + (-4) = 0 \] 6. Simplifying this gives: \[ x - 2 = 0 \implies x = +2 \] ### Step 3: Calculate the oxidation number of Mn in MnO₂ 1. The formula for manganese dioxide is MnO₂. 2. The oxidation number of oxygen (O) is -2, and there are 2 oxygen atoms, so: \[ 2(-2) = -4 \] 3. Let the oxidation number of Mn be \( x \). 4. Setting up the equation: \[ x + 2(-2) = 0 \] 5. Simplifying this gives: \[ x - 4 = 0 \implies x = +4 \] ### Step 4: Calculate the oxidation number of Mn in Mn₂O₃ 1. The formula for manganese(III) oxide is Mn₂O₃. 2. The oxidation number of oxygen (O) is -2, and there are 3 oxygen atoms, so: \[ 3(-2) = -6 \] 3. Let the oxidation number of Mn be \( x \), and since there are 2 manganese atoms, we have: \[ 2x + (-6) = 0 \] 4. Simplifying this gives: \[ 2x - 6 = 0 \implies 2x = 6 \implies x = +3 \] ### Summary of Oxidation Numbers - KMnO₄: +7 - K₂MnO₂: +2 - MnO₂: +4 - Mn₂O₃: +3 ### Conclusion The compound with the highest oxidation number of Mn is **KMnO₄** with an oxidation number of +7. ### Final Answer **A. KMnO₄**

To determine which compound has the highest oxidation number of manganese (Mn) among the given options, we will calculate the oxidation number of Mn in each compound step by step. ### Step 1: Calculate the oxidation number of Mn in KMnO₄ 1. The formula for potassium permanganate is KMnO₄. 2. The oxidation number of potassium (K) is +1. 3. The oxidation number of oxygen (O) is -2. 4. Let the oxidation number of Mn be \( x \). 5. The overall charge of the compound is neutral (0), so we can set up the equation: ...
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