In which of the following compounds oxidation state of chlorine has two different values?

Options

A. `CaCl_(2)`
B. `NaCl`
C. `CaOCl_(2)`
D. `C Cl_(4)`

Explanation

To determine in which of the given compounds the oxidation state of chlorine has two different values, we need to analyze the oxidation states of chlorine in each compound listed.

### Step-by-Step Solution:

1. **Identify the Compounds**: We need to check the oxidation states of chlorine in the following compounds:
- CaCl₂
- NaCl
- Ca(OCl)₂

2. **Calculate Oxidation States**:
- **For CaCl₂**:
- Calcium (Ca) has an oxidation state of +2.
- Let the oxidation state of chlorine (Cl) be x.
- The equation for the compound is:
\[ +2 + 2x = 0 \]
Solving for x gives:
\[ 2x = -2 \implies x = -1 \]
- Therefore, in CaCl₂, chlorine has an oxidation state of -1.

- **For NaCl**:
- Sodium (Na) has an oxidation state of +1.
- Let the oxidation state of chlorine be y.
- The equation for the compound is:
\[ +1 + y = 0 \]
Solving for y gives:
\[ y = -1 \]
- Therefore, in NaCl, chlorine also has an oxidation state of -1.

- **For Ca(OCl)₂**:
- Calcium (Ca) has an oxidation state of +2.
- The hypochlorite ion (OCl⁻) consists of one oxygen and one chlorine.
- Let the oxidation state of chlorine in OCl be z.
- The equation for the hypochlorite ion is:
\[ z + (-2) = -1 \quad (\text{since oxygen has an oxidation state of -2}) \]
Solving for z gives:
\[ z - 2 = -1 \implies z = +1 \]
- Therefore, in Ca(OCl)₂, one chlorine has an oxidation state of +1 (in OCl⁻) and the other chlorine (in the compound) has an oxidation state of -1.

3. **Conclusion**:
- In CaCl₂, chlorine has an oxidation state of -1.
- In NaCl, chlorine has an oxidation state of -1.
- In Ca(OCl)₂, chlorine has two different oxidation states: +1 and -1.
- Therefore, the compound in which chlorine has two different oxidation states is **Ca(OCl)₂**.

### Final Answer:
The compound in which the oxidation state of chlorine has two different values is **Ca(OCl)₂**.