Examples of few compounds in a particular oxidation state are given. Mark the example which is not correct.

Options

A. P in `H_(2)PO_(2)=+1`
B. Chlorine in +7 oxidation state `-HClO`
C. Chromium in +6 oxidation state `-CrO_(2)Cl_(2)`
D. Carbon in 0 oxidation state `-C_(12)H_(22)O_(11)`

Explanation

To solve the question regarding the oxidation states of various compounds and identify the incorrect example, we will analyze each option step by step.

### Step 1: Analyze Option 1 - H3PO2
1. **Identify the compound**: H3PO2 (phosphorous acid).
2. **Assign oxidation states**:
- Let the oxidation state of phosphorus (P) be \( x \).
- Hydrogen (H) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.
3. **Set up the equation**:
\[ 3(+1) + x + 2(-2) = 0 \]
\[ 3 + x - 4 = 0 \]
\[ x - 1 = 0 \implies x = +1 \]
4. **Conclusion**: The oxidation state of phosphorus in H3PO2 is +1, which matches the given information. So, this option is correct.

### Step 2: Analyze Option 2 - HClO
1. **Identify the compound**: HClO (hypochlorous acid).
2. **Assign oxidation states**:
- Let the oxidation state of chlorine (Cl) be \( x \).
- Hydrogen (H) is +1 and Oxygen (O) is -2.
3. **Set up the equation**:
\[ (+1) + x + (-2) = 0 \]
\[ 1 + x - 2 = 0 \]
\[ x - 1 = 0 \implies x = +1 \]
4. **Conclusion**: The oxidation state of chlorine in HClO is +1, which contradicts the given +7. Thus, this option is incorrect.

### Step 3: Analyze Option 3 - CrO2Cl2
1. **Identify the compound**: CrO2Cl2.
2. **Assign oxidation states**:
- Let the oxidation state of chromium (Cr) be \( x \).
- Oxygen (O) is -2 and Chlorine (Cl) is -1.
3. **Set up the equation**:
\[ x + 2(-2) + 2(-1) = 0 \]
\[ x - 4 - 2 = 0 \]
\[ x - 6 = 0 \implies x = +6 \]
4. **Conclusion**: The oxidation state of chromium in CrO2Cl2 is +6, which matches the given information. So, this option is correct.

### Step 4: Analyze Option 4 - C12H22O11
1. **Identify the compound**: C12H22O11 (sucrose).
2. **Assign oxidation states**:
- Let the oxidation state of carbon (C) be \( x \).
- Hydrogen (H) is +1 and Oxygen (O) is -2.
3. **Set up the equation**:
\[ 12x + 22(+1) + 11(-2) = 0 \]
\[ 12x + 22 - 22 = 0 \]
\[ 12x = 0 \implies x = 0 \]
4. **Conclusion**: The oxidation state of carbon in C12H22O11 is 0, which matches the given information. So, this option is correct.

### Final Conclusion
After analyzing all options, we find that the incorrect example is **Option 2** (HClO with Cl in +7 oxidation state).