Identify the oxidant and reductant in the following redox reaction:
`2K_(2)MnO_(4)+CI_(2)rarr2KCI+2KMnO_(4)`

Options

A. Oxidation of potassium manganate is taking place.
B. Reduction of potassium manganate is taking place.
C. Oxidation of `Cl_(2)` is taking place.
D. `Cl_(2)` acts as reducing agent in the reaction.

Explanation

To identify the oxidant and reductant in the given redox reaction:

**Reaction:**
\[ 2K_{2}MnO_{4} + Cl_{2} \rightarrow 2KCl + 2KMnO_{4} \]

### Step 1: Identify the oxidation states of manganese in K₂MnO₄ and KMnO₄.

1. **For K₂MnO₄:**
- Let the oxidation state of manganese (Mn) be \( x \).
- The oxidation states of potassium (K) is +1 and oxygen (O) is -2.
- The equation for the oxidation state is:
\[ 2(+1) + x + 4(-2) = 0 \]
- Simplifying this gives:
\[ 2 + x - 8 = 0 \implies x - 6 = 0 \implies x = +6 \]
- Thus, the oxidation state of Mn in K₂MnO₄ is +6.

2. **For KMnO₄:**
- Let the oxidation state of manganese (Mn) be \( y \).
- The equation for the oxidation state is:
\[ +1 + y + 4(-2) = 0 \]
- Simplifying this gives:
\[ 1 + y - 8 = 0 \implies y - 7 = 0 \implies y = +7 \]
- Thus, the oxidation state of Mn in KMnO₄ is +7.

### Step 2: Determine the change in oxidation state for manganese.

- The oxidation state of Mn changes from +6 in K₂MnO₄ to +7 in KMnO₄.
- Since the oxidation state increases, Mn is **oxidized**.

### Step 3: Identify the oxidation state of chlorine in Cl₂ and KCl.

1. **For Cl₂:**
- The oxidation state of chlorine in its elemental form (Cl₂) is 0.

2. **For KCl:**
- The oxidation state of chlorine in KCl is -1.

### Step 4: Determine the change in oxidation state for chlorine.

- The oxidation state of Cl changes from 0 in Cl₂ to -1 in KCl.
- Since the oxidation state decreases, Cl is **reduced**.

### Step 5: Identify the oxidant and reductant.

- The substance that gets oxidized (loses electrons) acts as the **reducing agent**. Here, K₂MnO₄ is oxidized, so it is the **reducing agent**.
- The substance that gets reduced (gains electrons) acts as the **oxidizing agent**. Here, Cl₂ is reduced, so it is the **oxidizing agent**.

### Conclusion:

- **Oxidant (oxidizing agent)**: Cl₂
- **Reductant (reducing agent)**: K₂MnO₄