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Consider the following reactions, (I) ...

Consider the following reactions,
(I) `SnCl_(2) + 2FeCl_(3) rarr SnCl_(4) + 2FeCl_(2)`

A

`SnCl_(2)` is oxidised and `FeCl_(3)` acts as oxidising agent.

B

`FeCl_(3)` is oxidised and acts as oxidising agent.

C

`SnCl_(2)` is reduced and acts as oxidising agent.

D

`FeCl_(3)` is oxidised and `SnCl_(2)` acts as a oxidising agent.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the given reaction and determine the oxidation states of the elements involved, we can follow these steps: ### Step-by-Step Solution: 1. **Write the Reaction**: The reaction given is: \[ \text{SnCl}_2 + 2\text{FeCl}_3 \rightarrow \text{SnCl}_4 + 2\text{FeCl}_2 \] 2. **Determine Oxidation States**: - For **SnCl₂**: - Let the oxidation state of Sn be \( x \). - The equation for the oxidation state is: \[ x + 2(-1) = 0 \implies x - 2 = 0 \implies x = +2 \] - Thus, the oxidation state of Sn in SnCl₂ is +2. - For **FeCl₃**: - Let the oxidation state of Fe be \( y \). - The equation for the oxidation state is: \[ y + 3(-1) = 0 \implies y - 3 = 0 \implies y = +3 \] - Thus, the oxidation state of Fe in FeCl₃ is +3. - For **SnCl₄**: - The oxidation state of Sn is: \[ z + 4(-1) = 0 \implies z - 4 = 0 \implies z = +4 \] - Thus, the oxidation state of Sn in SnCl₄ is +4. - For **FeCl₂**: - The oxidation state of Fe is: \[ w + 2(-1) = 0 \implies w - 2 = 0 \implies w = +2 \] - Thus, the oxidation state of Fe in FeCl₂ is +2. 3. **Identify Oxidation and Reduction**: - **Oxidation**: An increase in oxidation state. - Sn goes from +2 (in SnCl₂) to +4 (in SnCl₄). This is an increase in oxidation state, indicating that Sn is oxidized. - **Reduction**: A decrease in oxidation state. - Fe goes from +3 (in FeCl₃) to +2 (in FeCl₂). This is a decrease in oxidation state, indicating that Fe is reduced. 4. **Identify the Oxidizing and Reducing Agents**: - The substance that gets oxidized (SnCl₂) acts as a reducing agent. - The substance that gets reduced (FeCl₃) acts as an oxidizing agent. 5. **Conclusion**: - SnCl₂ is oxidized to SnCl₄. - FeCl₃ is reduced to FeCl₂. - Therefore, the correct statements are: - SnCl₂ is oxidized. - FeCl₃ acts as an oxidizing agent. ### Final Answer: - SnCl₂ is oxidized and FeCl₃ acts as an oxidizing agent.

To analyze the given reaction and determine the oxidation states of the elements involved, we can follow these steps: ### Step-by-Step Solution: 1. **Write the Reaction**: The reaction given is: \[ \text{SnCl}_2 + 2\text{FeCl}_3 \rightarrow \text{SnCl}_4 + 2\text{FeCl}_2 ...
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NCERT FINGERTIPS ENGLISH-REDOX REACTIONS-MCQs (OXIDATION NUMBER)
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  2. A compound contains atoms X,Y and Z. the oxidation number of X is +2, ...

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  8. Which of the following is a disproportionation reaction?

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  16. The number of moles of KMnO(4) reduced by 1 "mol of" KI in alkaline me...

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  17. Balance the following equation by oxidation number method: K(2)Cr(2)...

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