For the reaction : `I^(-)+ClO_(3)^(-)+H_(2)SO_(4) to Cl^(-)+HSO_(4)^(-)+I_(2)`
The incorrect statement for the balanced equation is:

Options

A. stoichiometric coefficient of `HSO_(4)^(-)` is 6
B. iodide is oxidized
C. sulphur is reduced
D. `H_(2)O` is one of the products.

Explanation

To solve the problem of identifying the incorrect statement for the balanced equation of the reaction:

**Given Reaction:**
\[ I^- + ClO_3^- + H_2SO_4 \rightarrow Cl^- + HSO_4^- + I_2 \]

**Step 1: Identify the Oxidation States**
- For \( I^- \) (iodide ion), the oxidation state is -1.
- For \( ClO_3^- \) (chlorate ion), the oxidation state of Cl can be calculated as follows:
- Let the oxidation state of Cl be \( x \).
- The equation for the oxidation state is \( x + 3(-2) = -1 \) (since there are three oxygen atoms each with -2 oxidation state).
- Solving gives \( x - 6 = -1 \) → \( x = +5 \).
- For \( Cl^- \) (chloride ion), the oxidation state is -1.
- For \( H_2SO_4 \) (sulfuric acid), the oxidation state of S can be calculated as:
- Let the oxidation state of S be \( x \).
- The equation for the oxidation state is \( x + 4(-2) + 2(+1) = 0 \).
- Solving gives \( x - 8 + 2 = 0 \) → \( x = +6 \).
- For \( HSO_4^- \) (hydrogen sulfate ion), the oxidation state of S remains +6.

**Step 2: Determine Changes in Oxidation States**
- Iodine changes from -1 in \( I^- \) to 0 in \( I_2 \), indicating oxidation (loss of electrons).
- Chlorine changes from +5 in \( ClO_3^- \) to -1 in \( Cl^- \), indicating reduction (gain of electrons).
- Sulfur remains at +6 in both \( H_2SO_4 \) and \( HSO_4^- \), indicating no change in oxidation state.

**Step 3: Balance the Reaction**
- The balanced equation can be derived by ensuring the number of atoms and charges are equal on both sides.
- Balancing oxygen and hydrogen can be done by adding water and hydrogen ions as necessary.

**Step 4: Analyze the Statements**
1. The stoichiometric coefficient of \( HSO_4^- \) is 6.
2. Iodine is oxidized.
3. Sulfur is reduced.
4. Water is one of the major products.

**Step 5: Identify the Incorrect Statement**
- From the analysis:
- Statement 1 is correct (stoichiometric coefficient of \( HSO_4^- \) is indeed 6).
- Statement 2 is correct (iodine is oxidized).
- Statement 3 is incorrect (sulfur is not reduced; it remains +6).
- Statement 4 is correct (water is a product).

**Conclusion:**
The incorrect statement is that sulfur is reduced.

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