Match list I with list II. Choose the correct matching codes from the choices given.
`{:(,"List I",,"List II"),(,"(Hydride)",,"(Type of hydride)"),(A.,BeH_(2),1.,"complex"),(B.,AsH_(3),2.,"Lewis acid"),(C.,B_(2)H_(6),3.,"Interstitial"),(D.,LaH_(3),4.,"Covalent"),(E.,LiAlH_(4),5.,"Intermediate"):}`

Options

A. A-6, B-2, C-4, D-5, E-1
B. A-6, B-2, C-4, D-3, E-1
C. A-6, B-4, C-2, D-3, E-5
D. A-5, B-4, C-2, D-3, E-1

Explanation

To solve the matching question between List I (Hydrides) and List II (Type of hydride), we will analyze each hydride one by one and determine their corresponding types.

### Step-by-Step Solution:

1. **Identify the first hydride: BeH₂ (Beryllium Hydride)**
- Beryllium has an electronic configuration of 1s² 2s². It has 2 electrons in its outer shell.
- In BeH₂, beryllium forms covalent bonds with two hydrogen atoms. However, it does not achieve a stable octet and behaves like an intermediate.
- **Match: A (BeH₂) → 5 (Intermediate)**

2. **Identify the second hydride: AsH₃ (Arsenic Hydride)**
- Arsenic has a lone pair and forms three covalent bonds with hydrogen, resulting in a pyramidal shape.
- This hydride is covalent in nature.
- **Match: B (AsH₃) → 4 (Covalent)**

3. **Identify the third hydride: B₂H₆ (Diborane)**
- Boron has an electronic configuration of 1s² 2s² 2p¹, meaning it has three valence electrons.
- B₂H₆ features unique three-center two-electron bonds, which makes it electron-deficient and allows it to act as a Lewis acid.
- **Match: C (B₂H₆) → 2 (Lewis acid)**

4. **Identify the fourth hydride: LaH₃ (Lanthanum Hydride)**
- Lanthanum can accommodate hydrogen in its structure and is known to form interstitial hydrides.
- **Match: D (LaH₃) → 3 (Interstitial)**

5. **Identify the fifth hydride: LiAlH₄ (Lithium Aluminum Hydride)**
- LiAlH₄ is a complex hydride, consisting of Li⁺ and AlH₄⁻ ions.
- **Match: E (LiAlH₄) → 1 (Complex)**

### Final Matching:
- A → 5 (Intermediate)
- B → 4 (Covalent)
- C → 2 (Lewis acid)
- D → 3 (Interstitial)
- E → 1 (Complex)

### Conclusion:
The correct matching codes are:
- A: 5
- B: 4
- C: 2
- D: 3
- E: 1

Thus, the answer is option D.