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Compound X on reduction with LiAlH(4) gi...

Compound X on reduction with `LiAlH_(4)` gives a hydride Y containing 21.72% hydrogen and other products. The compound Y reacts with air expolosively resulting in boron trioxide. What are X and Y respectively ?

A

`BCl_(3), B_(2)H_(6)`

B

`PCl_(3), B_(2)H_(6)`

C

`B_(2)H_(6), BCl_(3)`

D

`LiAlH_(4),PCl_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the compounds X and Y based on the given information. ### Step-by-Step Solution: 1. **Understanding the Reduction Reaction**: - Compound X is reduced by lithium aluminum hydride (LiAlH4) to form compound Y. - The reduction process typically involves the addition of hydrogen or the removal of oxygen. 2. **Analyzing Compound Y**: - Compound Y contains 21.72% hydrogen. To find its molecular formula, we can use the percentage composition. - The remaining percentage (100% - 21.72%) is attributed to other elements, which in this case would be boron (B). 3. **Calculating the Empirical Formula**: - Let's assume we have 100 g of compound Y. This means we have 21.72 g of hydrogen and 78.28 g of boron. - The molar mass of hydrogen (H) is approximately 1 g/mol, and for boron (B), it is approximately 10.81 g/mol. - Moles of hydrogen = 21.72 g / 1 g/mol = 21.72 mol - Moles of boron = 78.28 g / 10.81 g/mol ≈ 7.25 mol 4. **Finding the Ratio**: - The ratio of moles of boron to moles of hydrogen is approximately 7.25:21.72, which simplifies to about 1:3. - This suggests that the empirical formula of compound Y is B2H6 (diborane), which is consistent with the explosive reaction with air. 5. **Identifying Compound X**: - Given that Y is B2H6, we need to find a compound X that can produce B2H6 upon reduction with LiAlH4. - BCl3 (boron trichloride) is known to react with LiAlH4 to produce diborane (B2H6) and other by-products. - The balanced reaction is: \[ 2 BCl_3 + 6 LiAlH_4 \rightarrow B_2H_6 + 6 LiCl + 3 AlCl_3 \] 6. **Conclusion**: - Therefore, compound X is BCl3 and compound Y is B2H6. ### Final Answer: - X = BCl3 (Boron Trichloride) - Y = B2H6 (Diborane)

To solve the problem, we need to identify the compounds X and Y based on the given information. ### Step-by-Step Solution: 1. **Understanding the Reduction Reaction**: - Compound X is reduced by lithium aluminum hydride (LiAlH4) to form compound Y. - The reduction process typically involves the addition of hydrogen or the removal of oxygen. ...
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