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A solution of a compound X in dilute HCl...

A solution of a compound X in dilute HCl on treatment with a solution of `BaCl_(2)` gives a white precipitate of compound Y which is insoluble in conc. `HNO_(3)` and and conc. `HCl`. Compound X imparts golden yellow colour to the flame.
`underset(("immparts golden yellow colour"))(X("Solution in dilute HCl"))+BaCl_(2) to underset("White")(Y)underset("Conc. HCl")overset("Conc. "HNO_(3))to`Insoluble
What are compounds X and Y?

A

X is `MgCl_(2)` and Y is `BaSO_(4)`

B

X is `CaCl_(2) and Y` is `BaSO_(4)`

C

X is `Na_(2)SO_(4)` and Y is `BaSO_(4)`

D

X is `MgSO_(4)` and Y is `BaSO_(4)`

Text Solution

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The correct Answer is:
To solve the problem, we need to identify the compounds X and Y based on the information provided. ### Step-by-Step Solution: 1. **Identify Compound X**: - The problem states that compound X imparts a golden yellow color to the flame. - In flame tests, sodium salts (like sodium sulfate, Na₂SO₄) are known to impart a bright yellow color to the flame. - Other common s-block elements such as magnesium and calcium do not impart a golden yellow color (magnesium gives no color, and calcium gives a brick red color). - Therefore, we can conclude that compound X is likely sodium sulfate (Na₂SO₄). 2. **Reaction with BaCl₂**: - The next part of the problem states that when compound X (sodium sulfate) is treated with barium chloride (BaCl₂), it forms a white precipitate, which we will call compound Y. - The reaction can be written as: \[ \text{Na}_2\text{SO}_4 + \text{BaCl}_2 \rightarrow \text{BaSO}_4 \downarrow + 2\text{NaCl} \] - Here, barium sulfate (BaSO₄) is the white precipitate formed, which is compound Y. 3. **Insolubility of Compound Y**: - The problem also states that compound Y (barium sulfate) is insoluble in concentrated HNO₃ and concentrated HCl. - This is consistent with the known properties of barium sulfate, which is indeed insoluble in these acids. ### Conclusion: - Therefore, we can conclude that: - Compound X is sodium sulfate (Na₂SO₄). - Compound Y is barium sulfate (BaSO₄). ### Final Answer: - Compound X: Sodium sulfate (Na₂SO₄) - Compound Y: Barium sulfate (BaSO₄) ---

To solve the problem, we need to identify the compounds X and Y based on the information provided. ### Step-by-Step Solution: 1. **Identify Compound X**: - The problem states that compound X imparts a golden yellow color to the flame. - In flame tests, sodium salts (like sodium sulfate, Na₂SO₄) are known to impart a bright yellow color to the flame. - Other common s-block elements such as magnesium and calcium do not impart a golden yellow color (magnesium gives no color, and calcium gives a brick red color). ...
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NCERT FINGERTIPS ENGLISH-THE S-BLOCK ELEMENTS-Assertion And Reason
  1. A solution of a compound X in dilute HCl on treatment with a solution ...

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  2. Assertion: Elements of group 1 are called 'alkali metals'. Reason: A...

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  3. Assertion: Lithium resembles magnesium diagonally placed in next group...

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  4. Assertion: Alkali metals are obtained by electrolysis of molten salt a...

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  5. Assertion: Lithium salts are mostly hydrated. Reason: The hydration ...

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  6. Assertion: The melting and boiling points of the alkali metals are low...

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  7. Assertion: Lithium fluoride is most covalent in nature. Reason: Smal...

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  8. Assertion: The carbonate of lithium decomposes easily on heating. Re...

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  9. Assertion : Super-oxides of alkali metals are para-magnetic. Reason ...

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  10. Assertion: Be and Mg do not impat characteristic colour to the flame. ...

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  11. Assertion: The fluorides of alkaline earth metals are relatively less ...

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  12. Assertion: Be is readily attacked by acids. Reason: Be shows diagona...

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  13. Assertion: Alkaline earth metal oxides are quite stable to heat. Rea...

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  14. Assertion: BeSO(4) and MgSO(4) are insoluble in water. Reason: Be^(2...

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  15. Assertion: CaCO(3) is prepared by passing carbon dioxide gas through s...

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  16. Assertion: For biological functions in human body, barium is not requi...

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