A certain compound X impats golden yellow flame. Whenzinc powder is heated with concenrated solution of X, `H_(2)` gas is evolved. X combines with `CO_(2)` to give a salt Y. Y is a hydrated salt which on reaction with HCl or ecess of `CO_(2)` gives another salt Z which is an important part of baking powder. identify X, Y and Z.

Options

A. `X-NaOH,Y-Na_(2)CO_(3),Z-NaHCO_(3)`
B. `X-HCl, Y-NaOH,Z-NaHCO_(3)`
C. `X-KOH,Y-K_(2)CO_(3),Z-KHCO_(3)`
D. `X-NaCl,Y-Na_(2)CO_(3),Z-NaOH`

Explanation

To solve the problem, we need to identify the compounds X, Y, and Z based on the clues provided in the question. Let's break down the information step by step.

### Step 1: Identify Compound X
The question states that compound X imparts a golden yellow flame. In chemistry, sodium (Na) is known to produce a golden yellow flame when burned. Therefore, we can conclude that:

**X = Sodium hydroxide (NaOH)**

### Step 2: Reaction of X with Zinc
Next, we are told that when zinc powder is heated with a concentrated solution of X (which we identified as NaOH), hydrogen gas (H₂) is evolved. The reaction can be written as:

\[ \text{Zn} + 2 \text{NaOH} \rightarrow \text{Na}_2\text{ZnO}_2 + \text{H}_2 \]

This confirms that our identification of X as sodium hydroxide is correct.

### Step 3: Identify Compound Y
The question states that X combines with CO₂ to give a salt Y. Sodium hydroxide reacts with carbon dioxide to form sodium carbonate:

\[ 2 \text{NaOH} + \text{CO}_2 \rightarrow \text{Na}_2\text{CO}_3 + \text{H}_2\text{O} \]

Thus, we can identify:

**Y = Sodium carbonate (Na₂CO₃)**

### Step 4: Identify Compound Z
The question mentions that Y is a hydrated salt which, upon reaction with HCl or excess CO₂, gives another salt Z that is an important part of baking powder. Sodium carbonate (Na₂CO₃) can react with hydrochloric acid (HCl) to produce sodium bicarbonate (NaHCO₃):

\[ \text{Na}_2\text{CO}_3 + \text{HCl} \rightarrow \text{NaHCO}_3 + \text{NaCl} \]

Sodium bicarbonate is also produced when sodium carbonate reacts with excess CO₂:

\[ \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O} \rightarrow 2 \text{NaHCO}_3 \]

Thus, we can identify:

**Z = Sodium bicarbonate (NaHCO₃)**

### Conclusion
In summary, we have identified the compounds as follows:
- **X = Sodium hydroxide (NaOH)**
- **Y = Sodium carbonate (Na₂CO₃)**
- **Z = Sodium bicarbonate (NaHCO₃)**