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The violet flame shown by potassium in b...

The violet flame shown by potassium in bunsen flame is due to jumping of the electron from

A

1s to 4p

B

1s tto 5p

C

4p to 4s

D

5p to 4s

Text Solution

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The correct Answer is:
To solve the question regarding the violet flame shown by potassium in a Bunsen flame, we need to understand the electronic transitions that occur when potassium is heated. Here is a step-by-step solution: ### Step 1: Understand the Electronic Configuration of Potassium Potassium (K) has an atomic number of 19, which means it has 19 electrons. The electronic configuration of potassium is: - 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ ### Step 2: Identify the Excited State When potassium is heated in a Bunsen flame, the energy from the flame excites the outermost electron (which is in the 4s orbital) to a higher energy level. The relevant higher energy levels for potassium include the 4p and 5p orbitals. ### Step 3: Determine the Transition Responsible for the Violet Flame The violet color in the flame is due to the transition of the excited electron from a higher energy level back to a lower energy level. In this case, the electron jumps from the 5p orbital back to the 4s orbital. ### Step 4: Identify the Correct Option Looking at the options provided: - A: 1s to 4p - B: 1s to 5p - C: 4p to 4s - D: 5p to 4s The correct transition that produces the violet color is from the 5p to the 4s orbital. Therefore, the correct answer is option D. ### Final Answer The violet flame shown by potassium in a Bunsen flame is due to the jumping of the electron from the 5p to the 4s orbital. ---
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