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In BX(3) B - X distance is shorter than ...

In `BX_(3)` B - X distance is shorter than what is expected theoretically because (X = F, CI, Br, I)

A

`sp^(3)` hybridisation of B is responsible for shorter B - X distance

B

B- X has a double bond character due to back-bonding

C

Dimerisation takes place in `BX_(3)` which is responsible for shorter B - X distance.

D

Due to large size, of X, B - X distance decreases.

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The correct Answer is:
B
Due to back-bonding B- X in `BX_(3)` has double bond character which because of resonance result in shorter B-X distance
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