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Na(2)B(4)O(7). 10H(2) O overset(Delta)(t...

`Na_(2)B_(4)O_(7). 10H_(2) O overset(Delta)(to) X overset(Delta)(to) Y + Z ,X Y` and Z in the reaction are

A

`X = Na_(2)B_(4)O_(7), Y NaBO_(2), Z = B_(2)O_(3)`

B

`X = Na_(2)B_(4)O_(7), Y = B_(2)O_(3), Z=H_(3)BO_(3)`

C

`X = B_(2)O_(3), Y = NaBO_(2), Z = B (OH)_(3)`

D

`X = NaBO_(2), Y = B_(2)O_(3), Z = B(OH)_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the thermal decomposition of borax, which is represented by the formula \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \). ### Step-by-Step Solution: 1. **Identify the Compound**: The compound given is borax, \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \). It is a hydrated sodium borate. **Hint**: Recognize the formula and its components, including the water of hydration. 2. **Heating Borax**: When borax is heated, it loses its water molecules. The dehydration process can be represented as: \[ \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \xrightarrow{\Delta} \text{Na}_2\text{B}_4\text{O}_7 + 10\text{H}_2\text{O} \] Here, \( \Delta \) represents heating. **Hint**: Understand that heating causes the loss of water, leading to the formation of anhydrous sodium tetraborate. 3. **Further Heating**: Upon further heating of \( \text{Na}_2\text{B}_4\text{O}_7 \), it decomposes to form sodium metaborate and boron trioxide: \[ \text{Na}_2\text{B}_4\text{O}_7 \xrightarrow{\Delta} 2\text{NaBO}_2 + \text{B}_2\text{O}_3 \] **Hint**: Recognize that the decomposition of sodium tetraborate leads to the formation of two different products. 4. **Identify the Products**: - The first product formed after the initial heating (compound X) is \( \text{NaBO}_2 \) (sodium metaborate). - The second product (compound Y) is \( \text{NaBO}_2 \). - The third product (compound Z) is \( \text{B}_2\text{O}_3 \) (boron trioxide). **Hint**: Keep track of the stoichiometry and the types of compounds produced during the decomposition. 5. **Final Identification**: - \( X = \text{NaBO}_2 \) (sodium metaborate) - \( Y = \text{NaBO}_2 \) (sodium metaborate) - \( Z = \text{B}_2\text{O}_3 \) (boron trioxide) ### Conclusion: The final answer is: - \( X = \text{NaBO}_2 \) - \( Y = \text{NaBO}_2 \) - \( Z = \text{B}_2\text{O}_3 \) ### Summary of Steps: 1. Identify the compound as borax. 2. Understand the dehydration process upon heating. 3. Recognize the further decomposition products. 4. Identify the final products based on the reaction.

To solve the problem, we need to analyze the thermal decomposition of borax, which is represented by the formula \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \). ### Step-by-Step Solution: 1. **Identify the Compound**: The compound given is borax, \( \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \). It is a hydrated sodium borate. **Hint**: Recognize the formula and its components, including the water of hydration. ...
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