`NaBH_(4) + I_(2) to X + Y + Z`
`BF_(3) + NaH overset(450K)(to) X + P`
`BF_(3) + LiAIH_(4) to X + Q + R`
X,Y,Z,P,Q and R reaction are
`{:(X,Y,Z,P,Q,R):}`

Options

A. `{:(Na_(4)B_(4)O_(7),NaI,HI,HF,LiF,AIF_(3)):}`
B. `{:(B_(2)H_(6),NaI,H_(2),NaF,LiF,AIF_(2)):}`
C. `{:(B_(2)H_(6),BH_(3),NaI,B_(3)N_(3)H_(6),AI_(2)F_(6),AIF_(3)):}`
D. `BH_(3),B_(2)H_(6),H_(2),B_(3)N_(3)H_(6),LiF,AIF_(3)`

Explanation

To solve the given reactions step by step, we will analyze each reaction and identify the products (X, Y, Z, P, Q, and R).

### Step 1: Reaction of NaBH₄ with I₂
The reaction is:
\[ \text{NaBH}_4 + \text{I}_2 \rightarrow X + Y + Z \]

**Products:**
- When sodium borohydride (NaBH₄) reacts with iodine (I₂), it produces diborane (B₂H₆), sodium iodide (NaI), and hydrogen gas (H₂).
- The balanced equation is:
\[ 2 \text{NaBH}_4 + \text{I}_2 \rightarrow \text{B}_2\text{H}_6 + 2 \text{NaI} + H_2 \]

Thus, we can identify:
- **X = B₂H₆**
- **Y = NaI**
- **Z = H₂**

### Step 2: Reaction of BF₃ with NaH
The reaction is:
\[ \text{BF}_3 + \text{NaH} \overset{450K}{\rightarrow} X + P \]

**Products:**
- When boron trifluoride (BF₃) reacts with sodium hydride (NaH), it produces diborane (B₂H₆) and sodium fluoride (NaF).
- The balanced equation is:
\[ 2 \text{BF}_3 + 6 \text{NaH} \rightarrow \text{B}_2\text{H}_6 + 6 \text{NaF} \]

Thus, we can identify:
- **X = B₂H₆**
- **P = NaF**

### Step 3: Reaction of BF₃ with LiAlH₄
The reaction is:
\[ \text{BF}_3 + \text{LiAlH}_4 \rightarrow X + Q + R \]

**Products:**
- When boron trifluoride (BF₃) reacts with lithium aluminum hydride (LiAlH₄), it produces diborane (B₂H₆), lithium fluoride (LiF), and aluminum fluoride (AlF₃).
- The balanced equation is:
\[ 3 \text{BF}_3 + 4 \text{LiAlH}_4 \rightarrow \text{B}_2\text{H}_6 + 3 \text{LiF} + \text{AlF}_3 \]

Thus, we can identify:
- **X = B₂H₆**
- **Q = LiF**
- **R = AlF₃**

### Summary of Products:
- **X = B₂H₆**
- **Y = NaI**
- **Z = H₂**
- **P = NaF**
- **Q = LiF**
- **R = AlF₃**

### Final Answer:
The products are:
- \( X = \text{B}_2\text{H}_6 \)
- \( Y = \text{NaI} \)
- \( Z = \text{H}_2 \)
- \( P = \text{NaF} \)
- \( Q = \text{LiF} \)
- \( R = \text{AlF}_3 \)