`SiCl_(4) overset(H_(2)O)(to) X overset("Heat")(to) Y overset(NaOH)(to) Z`
find X,Y,Z.

Options

A. `{:(SiO_(2), Si,NaSi):}`
B. `{:(Si(OH)_(4),SiO_(2),Na_(2)SiO_(3)):}`
C. `{:(Si(OH)_(4),Si,SiO_(2)):}`
D. `{:(SiO_(2),SiCI_(4),Na_(2)SiO_(3)):}`

Explanation

To solve the problem step by step, we will analyze the reactions involving SiCl₄, H₂O, heat, and NaOH.

### Step 1: Reaction of SiCl₄ with H₂O
When silicon tetrachloride (SiCl₄) reacts with water (H₂O), it produces orthosilicic acid (Si(OH)₄) and hydrochloric acid (HCl). The balanced reaction is:

\[ \text{SiCl}_4 + 4 \text{H}_2\text{O} \rightarrow \text{Si(OH)}_4 + 4 \text{HCl} \]

**X = Si(OH)₄ (orthosilicic acid)**

### Step 2: Heating Si(OH)₄
When orthosilicic acid (Si(OH)₄) is heated, it decomposes into silica (SiO₂) and water (H₂O). The balanced reaction is:

\[ \text{Si(OH)}_4 \rightarrow \text{SiO}_2 + 2 \text{H}_2\text{O} \]

**Y = SiO₂ (silica)**

### Step 3: Reaction of SiO₂ with NaOH
Silica (SiO₂) is acidic in nature and reacts with sodium hydroxide (NaOH) to form sodium silicate (Na₂SiO₃) and water. The balanced reaction is:

\[ \text{SiO}_2 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{SiO}_3 + \text{H}_2\text{O} \]

**Z = Na₂SiO₃ (sodium silicate)**

### Summary of Results
- **X = Si(OH)₄ (orthosilicic acid)**
- **Y = SiO₂ (silica)**
- **Z = Na₂SiO₃ (sodium silicate)**