In the following reactions
`2X+B_(2)H_(6) to [BH_(2)(X)_(2)]^(+){BH_(4)]^(-)`
The amine X will not be -

Options

A. `NH_(3)`
B. `CH_(3)NH_(2)`
C. `(CH)_(3))_(2) NH`
D. `(CH_(3))_(3)n`

Explanation

To solve the question, we need to analyze the reaction between diborane (B₂H₆) and the amine (X) to determine which type of amine will not participate in the reaction to form the given products.

### Step-by-Step Solution:

1. **Understanding the Reaction**: The reaction given is:
\[ 2X + B_2H_6 \rightarrow [BH_2(X)_2]^+ + [BH_4]^- \]
Here, X represents an amine that reacts with diborane.

2. **Types of Amines**: Amines can be classified into three categories:
- Primary amines (RNH₂)
- Secondary amines (R₂NH)
- Tertiary amines (R₃N)

3. **Reactivity of Amines with Diborane**: Diborane (B₂H₆) can undergo unsymmetrical cleavage when reacting with primary and secondary amines. This means that it can form products with these types of amines.

4. **Unsymmetrical Cleavage**: When diborane reacts with primary or secondary amines, it leads to the formation of:
\[ [BH_2(X)_2]^+ \text{ and } [BH_4]^- \]
This is due to the unsymmetrical cleavage of the B-H bonds in diborane.

5. **Tertiary Amines**: In contrast, tertiary amines (R₃N) are bulky and do not allow for the same type of reaction. Instead, they lead to symmetrical cleavage of diborane, which does not yield the products specified in the question.

6. **Conclusion**: Since tertiary amines do not participate in the reaction to form the specified products, we conclude that the amine X will not be a tertiary amine.

### Final Answer:
The amine X will not be a tertiary amine.